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Arisa [49]
3 years ago
8

2+90=? please someone help asap

Mathematics
2 answers:
dimulka [17.4K]3 years ago
5 0

Answer:

92

Hope this helped cause this was hard to solve bye(⁄ ⁄>⁄ ▽ ⁄<⁄ ⁄)

Oxana [17]3 years ago
4 0

Answer:

92 :)

Step-by-step explanation:

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The exact value of sin (-270) is determined using the calculator in degrees mode. The answer is equal to 1. If the radians mode is used, -270 is equal to -2 pi/3. Hence using the calculator, we can verify that the answer is still 1. The value of -270 matters.
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Determine which postulate can be used
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SAS postulate

Step-by-step explanation:

The triangles have two congruent sides and one congruent angle. The congruent angle is the included angle. This meets SAS criteria.

<u>Hope this helps :-)</u>

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3 years ago
If line b is perpendicular to line a, and line c is
Nikolay [14]

Answer:

y=x-2.5

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8 0
3 years ago
A person purchased a slot machine and tested it by playing it 1,137 times. There are 10 different categories of outcomes, includ
ivann1987 [24]

Answer:

p_v= P(\chi^2_{9}>11.517)=0.2419

And on this case if we see the significance level given \alpha=0.1 we see that p_v>alpha so we fail to reject the null hypothesis that the observed outcomes agree with the expected frequencies at 10% of significance.

Step-by-step explanation:

A chi-square goodness of fit test determines if a sample data obtained fit to a specified population.

p_v represent the p value for the test

O= obserbed values

E= expected values

The system of hypothesis for this case are:

Null hypothesis: O_i = E_i[/tex[Alternative hypothesis: [tex]O_i \neq E_i

The statistic to check the hypothesis is given by:

\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

On this case after calculate the statistic they got: \chi^2 = 11.517

And in order to calculate the p value we need to find first the degrees of freedom given by:

df=n-1=10-1=9, where k represent the number of levels (on this cas we have 10 categories)

And in order to calculate the p value we need to calculate the following probability:

p_v= P(\chi^2_{9}>11.517)=0.2419

And on this case if we see the significance level given \alpha=0.1 we see that p_v>alpha so we fail to reject the null hypothesis that the observed outcomes agree with the expected frequencies at 10% of significance.

6 0
3 years ago
Is 63.90 greater than 63.990
djverab [1.8K]

Answer:

63.90 is greater than63.990

3 0
2 years ago
Read 2 more answers
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