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OlgaM077 [116]
3 years ago
6

Please help will give brainliest

Mathematics
1 answer:
kogti [31]3 years ago
4 0

Answer:

y = 3/2x + 0

Step-by-step explanation:

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A.<br> 18<br><br><br> B.<br> 36<br><br><br> C.<br> 72<br><br><br> D.<br><br><br> 216
DerKrebs [107]
The least common denominator would be B. 36
4 0
3 years ago
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A car is traveling at a speed of 30.0m/s encounters an emergency and comes to complete stop how much time will it take for the c
Travka [436]

Answer:

7.5\ seconds

Step-by-step explanation:

The Equation of motion is given by

v=u-at\\\\\ v:Final\ Velocity\\u:Initial\ Velocity\\a:acceleration\\t:time

Herev=0(as\ at\ the\ end\ car\ stops), u=30m/s,a=-4m/s^2

0=30-4t\\\\4t=30\\\\t=\frac{30}{4}\\\\t=7.5\ seconds

8 0
3 years ago
A natural number is an irrational number sometimes always never
Nady [450]

Answer:

always

Step-by-step explanation:

. Always. Real numbers are irrational numbers. ... Natural numbers are rational numbers.

8 0
3 years ago
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1. A food safety guideline is that the mercury in fish should be below 1 part per million​ (ppm). Listed below are the amounts o
Sauron [17]

Answer:

The confidence interval estimate of the population mean is :

(0.61 ppm, 0.90 ppm)

The correct option is (A).

Step-by-step explanation:

The amounts of mercury​ (ppm) found in tuna sushi sampled at different stores in a major city are:

S = {0.58, 0.82, 0.10, 0.98, 1.27, 0.56, 0.96}

A (100-\alpha )\% confidence interval for the population mean (μ) is an interval estimate of the true value of the mean. This interval has a (100-\alpha )\% probability of consisting the true value of mean.

⇒ Since the population standard deviation is not provided we will use the <em>t</em>-distribution to construct the 99% confidence interval for mean.

⇒ The formula for confidence interval for the population mean is:

                                          \bar x\pm t_{\alpha/2,(n-1)}\times \frac{s}{\sqrt{n}}

Here,

\bar x = sample mean

<em>s </em>= sample standard deviation

<em>n</em> = sample size

t_{\alpha/2,(n-1)} = critical value.

The degrees of freedom for the critical value is, (<em>n</em> - 1) = 7 - 1 = 6.

The significance level is: \alpha =1-Confidence\ level=1-0.99=0.01

The critical value is:

t_{\alpha/2,(n-1)}=t_{0.01/2, 7}=t_{0.05,7}=3.143

**Use the <em>t</em>-table for the critical value.

Compute the sample mean and sample standard deviation as follows:

\bar x=\frac{1}{7}(0.58+ 0.82+ 0.10+ 0.98+ 1.27+ 0.56+ 0.96) =0.753

\int\limits^a_b {x} \, dx s=\sqrt{\frac{\sum (x{i}-\bar x)^{2}}{n-1} } =\sqrt{\frac{1}{6} \times 0.859743} =0.379

The 99% confidence interval for μ is:

x^{2} CI=0.753\pm 3.143\times\frac{0.379}{\sqrt{7}} \\=0.753\pm0.143\\=(0.61, 0.896)\\\approx(0.61, 0.90)

The confidence interval estimate of the population mean is:

(0.61 ppm, 0.90 ppm)

The upper and lower limit of the 99% confidence interval indicates that the true mean value is less than 1 ppm. This implies that there is not too much mercury in tuna sushi

Because it is possible that the mean is not greater than 1 ppm. Also, at least one of the sample values is less than 1 ppm, so at least some of the fish are safe.

Thus, the correct option is (A).

6 0
3 years ago
Wastewater is filling barrels at the rate of 11 quarts per hour. The recycling facility picks up 120 full barrels on each trip,
dalvyx [7]
(1 h)/(11 qt) * (12 qt)/(1 barrel) * (120 barrels/pickup) * (1 day)/(24 h)
.. = 12*120/(11*24) day/pickup
.. = 5 5/11 days/pickup

120 barrels will be filled every 5 5/11 days. Some trips will be 5 days apart, some trips will be 6 days apart.
8 0
3 years ago
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