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3 years ago

I have two coins totaling 15 cents. One of them is it a nickel. What are they?

Mathematics

1 answer:

Aloiza [94]3 years ago

5 0

One is a nickel and the other is a dime

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Aliza needs to run at a rate faster than 8.8 ft per second in order to exceed her fastest time in a race after running for 15 mi

HACTEHA [7]

He used an incorrect time ratio converting hours to minutes.

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4 years ago

Select each expression that has a value of 36 when x = 12.

pogonyaev

Answer:

Option c

Step-by-step explanation:

if x = 12

12^2 = 144

144/18 = 8

28 + 8 = 36

6 0

3 years ago

Find the value of X and the value of Y. <br> (10 POINTS)

Ganezh [65]

sin 45 = opp/hyp

sin 45 = 4 / y

y = 4/sin 45

y = 4 /((sqrt2)/2)=4* sqrt(2)

tan 45 =opp/adj

tan 45 = 4/(x-3)

1 = 4/(x-3)

x-3 = 4

x=7

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3 years ago

Words that came from the same ancestral language and originated from the same word are called

Anna71 [15]

Words that came from the same ancestral language and originated from the same word are called COGNATE WORDS.

In linguistics, cognates are words that have a common etymological origin. These are words in two languages that share a similar meaning, spelling, and pronunciation. For an instance, English words have lots of related words in Spanish.

8 0

3 years ago

Read 2 more answers

A biologist is studying the elk population in a county park. She starts with only 2 elk and observes that the number of elk trip

DochEvi [55]

Answer:

The expression that represents the population of elk is: $\text{elk}(t) = 2*3^t$ . It'll take 6 years for the population to reach 1,458 individuals.

Step-by-step explanation:

Since the number of elks triples every year and starts at $\text{elk}(0) = 2$ , then after the first year the population will be:

$\text{elk}(1) = \text{elk}(0)*3 = 2*3$

While on the second year, it'll be:

$\text{elk}(2) = \text{elk}(1)*3 = 2*3*3 = 2*3^2$

On the third year:

$\text{elk}(3) = \text{elk}(2)*3 = 2*3^2*3 = 2*3^3$

And so on, therefore the expression that describes the population of elk as the years passes is:

$\text{elk}(t) = 2*3^t$

If we want to know the number of years until the population reach 1,458 elk, we need to apply this value to the left side of the equation and solve for t.

$1458 = 2*3^t\\3^t = \frac{1458}{2}\\3^t = 729\\ln(3^t) = ln(729)\\t*ln(3) = ln(729)\\t = \frac{ln(729)}{ln(3)} = 6$

The population will reach 1,458 elk in 6 years.

8 0

3 years ago