Maybe its true i am not sure
Options :
A.) s1 < s2
B.) s1 <= s2
C.) s1.compareTo(s2) == −1
D.) s2.compareTo(s1) < 0
E.) s1.compareTo(s2) < 0
Answer: E.) s1.compareTo(s2) < 0
Explanation: Lexicographical ordering simply means the arrangement of strings based on the how the alphabets or letters of the strings appear. It could also be explained as the dictionary ordering principle of words based on the arrangement of the alphabets. In making lexicographical comparison between strings, the compareTo () method may be employed using the format below.
If first string = s1 ; second string = s2
To compare s1 with s2, the format is ;
s1.compareTo(s2) ;
If s1 comes first, that is, before s2, the method returns a negative value, that is a value less than 0 '< 0', which is the case in the question above.
If s2 comes first, that is, before s1, the method returns a positive value, that is a value greater than 0 '> 0'.
If both are s1 and s2 are the same, the output will be 0.
Answer:
si gigi hadid tapos si bella poarch
Explanation:
Answer:
D. Identify the problem.
Explanation:
There are six steps or stages in computer system troubleshooting. They are,
1. Identify the problem: In the stage of troubleshooting, the user is interviewed to get a description of the problem. Reproducing the problem is essential to confirm the described problem of the system before moving to the next stage.
2. Establish a theory of probable cause: when the problem is identified, a list of the possible cause of the problem is made.
3. Test the theory to determine a cause: each items on the list of possible cause of the problem is tested to confirm its actual cause.
4. Resolve the problem.
5. Verify full system functionality
6. Document the findings, actions and outcomes.
Answer:
range [0, 7) an odd column index in the range [3, 8) This can be accomplished in a single line.
def PROBLEM3 (input_matrix):
# YOUR CODE GOES HERE
return output_matrix
# DO NOThern bus under
