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3 years ago

Please help and show work asap!:)

Mathematics

1 answer:

andreev551 [17]3 years ago

3 0

Answer:

Step-by-step explanation:

A = πR² = π(2²) = 3.14(4) = 12.56 = 12.6 yd²

C = 2πR = 2(3.14)(2) = 12.56 = 12.6 yd

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Ann wants to buy a used car and needs to have a down payment of 35%. If the car Ann wants to buy costs $3,000, how much down pay

Inga [223]

Answer:

Ann will need a down payment of 1050 dollars

Step-by-step explanation:

The answer is 1050 because 35% of 3000 is 1050.

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3 years ago

Find the volume of the earth if the diameter is 7917.5

ira [324]

Answer:

Step-by-step explanation:

diameter=7917.5

r=3958.75

the earth is sphere

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3 years ago

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BARSIC [14]

Answer:

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3 years ago

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If f(x) = 3x + 2, what is f(5)?

Minchanka [31]

Answer:

Step-by-step explanation:

1. 3(5) + 2

2. 15 + 2

3. 17

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3 years ago

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An internal study by the Technology Services department at Lahey Electronics revealed company employees receive an average of 4.

Leno4ka [110]

Answer:

P(4 non-work-related e-mails)=0.1933

P(7 or more non-work-related e-mails)=0.1442

P(3 or less non-work-related e-mails)=0.3771

Step-by-step explanation:

A Poisson distribution is useful to measure the probability of a number of events in a given period, in this problem, receiving a non-work-related e-mail would be the event and an hour would be the period of time.

Its probability mass function is $f(k; \lambda) = P(x=k) = \frac{\lambda^k e^{-\lambda}}{k!}$ , being k the number of events and λ how many sucesses (events) are per period of time (4.3 in this case)

First, we calculate what is the probability of receiving exactly 4 e-mails:

$f(k; \lambda) =P(k=4) =\frac{4.3^4 e^{-\4.3}}{4!}=0.1933$

As k is a discrete variable, to know the joint probability of different number of events we add the probability of each value.

The probability of receiving 7 or more is the sum of P(7), P(8), ..., P(∞):

$P(k\geq 7 ) =\sum_{i=7}^{\infty}\frac{4.3^i e^{-\4.3}}{i!}=0.1442$

Last, the probability of receiving 3 or less is the sum of P(0), P(1), P(2) and P(3):

$P(k\leq3 ) =\sum_{i=0}^{3}\frac{4.3^i e^{-\4.3}}{i!}=0.3771$

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3 years ago