3 years ago

Please help me i dont know how to do any of this

Mathematics

1 answer:

Valentin [98]3 years ago

3 0

I think its... A (but not sure)

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3a+a+2a-5a? Can someone give me the answer please? Ty

Shkiper50 [21]

Answer:

Step-by-step explanation:

=3a + a + 2a - 5a

=4a - 3a

= a

hope it helps u tate!

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3 years ago

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What is the slope of (3, 3) and (-6, -3)

Veronika [31]

Answer:

m=2/3

Step by Step Explanation:

x1,y1= 3,-6

x2,y2=3,-3

m={-3-3} (Fraction Form)

{-6-3}

Refine:

m={2}{3}

7 0

3 years ago

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Please. Answer Fast! Use composition to determine if G(x) or H(x) is the inverse of F(x) for the

s344n2d4d5 [400]

Answer:

A. H(x) is an inverse of F(x)

Step-by-step explanation:

The given functions are:

$F(x)=\sqrt{x-2}$

$G(x)=(x-2)^2$

$H(x)=x^2+2$

We compose F(x) and G(x) to get:

$(F\circ G)(x)=F(G(x))$

$(F\circ G)(x)=F((x-2)^2)$

$(F\circ G)(x)=\sqrt{(x-2)^2-2}$

$(F\circ G)(x)=\sqrt{x^2-4x+4-2}$

$(F\circ G)(x)=\sqrt{x^2-4x+2}$

$(F\circ G)(x)\ne x$

Hence G(x) is not an inverse of F(x).

We now compose H(x) and G(x).

$(F\circ H)(x)=F(H(x))$

$(F\circ H)(x)=F(x^2+2)$

$(F\circ H)(x)=\sqrt{x^2+2-2}$

We simplify to get:

$(F\circ H)(x)=\sqrt{x^2}$

$(F\circ H)(x)=x$

Since $(F\circ H)(x)=x$ , H(x) is an inverse of F(x)

3 0

3 years ago

Factor completely, then place the factors in the proper location on the grid.

Lyrx [107]

4(x+5y)(x-3y)
I don't know what you mean by placing the factors on the grid

6 0

3 years ago

Please help!!!!!!!!!

kotykmax [81]

10+6+9+13+7= 45

and divide it by 5

the answer is 9

8 0

3 years ago

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