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2 years ago

Will give Brainly if correct

Mathematics

1 answer:

Fiesta28 [93]2 years ago

4 0

Answer:

x=34 because opposite angles

y=34 because 180-146=34

z=112 because opposite angles

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Solve the equation for y (picture below)<br> Please show work and solve as much as you can

Alina [70]

2)
4x-10y=12

Subtract 4x from each side.
-10y=-4x+12

Divide both sides by -10
y=2/5x-6/5

3)
13=1/6y+2x

Subtract 2x from each side.
-2x+13=1/6y

Multiply both sides by 6.
-12x+78=y

Flip it around.
y=-12x+78

Hope this helps!

5 0

3 years ago

How many ways are there to distribute five balls into seven boxes if?

katovenus [111]

There are a lot of ways but here are a couple of examples.
1. 1,2,3,4,5 - 1,2,4,5,3 - 1,4,5,3,2...... So on Hope this helps:)

3 0

3 years ago

What is 2.5/10 (fraction) simplified?

sladkih [1.3K]

Answer:

-1

—— = -0.25000

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

the length of a rectangle is 3 units shorter than one -third of the width, x. Which expression represents the perimeter of the r

Mariana [72]

Answer:

A) $\frac{8}{3} x - 6$

Step-by-step explanation:

Let the width of the rectangle be x units.

$\therefore \: length \: of \: rectangle = \frac{1}{3} x - 3 \\ Perimeter \: of \: rectangle = 2(l + w) \\ = 2 \bigg( \frac{1}{3} x - 3 + x \bigg)\\ = 2 \bigg( x + \frac{1}{3} x - 3 \bigg)\\ = 2 \bigg( \frac{3x + x}{3} - 3 \bigg)\\ = 2 \bigg( \frac{4x}{3} - 3 \bigg) \\ = 2 \bigg( \frac{4x}{3} - 3 \bigg) \\ = \frac{2 \times 4x}{3} -2 \times 3 \\ \purple{ \bold{{Perimeter \: of \: rectangle = \frac{8}{3} x - 6}}}$

8 0

3 years ago

Evaluate the integral ∫2−1|x−1|dx

defon

I think you might be referring to the definite integral,

$\displaystyle \int_{-1}^2|x-1|\,\mathrm dx$

Recall the definition of absolute value:

$|x| = \begin{cases}x&\text{if }x\ge0\\-x&\text{if }x$

Then $|x-1|=x-1$ if $x\ge1$ , and $|x-1|=1-x$ is $x$ . So spliting up the integral at <em>x</em> = 1, we have

$\displaystyle \int_{-1}^2|x-1|\,\mathrm dx = \int_{-1}^1(1-x)\,\mathrm dx + \int_1^2(x-1)\,\mathrm dx$

The rest is simple:

$\displaystyle \int_{-1}^2|x-1|\,\mathrm dx = \left(x-\dfrac{x^2}2\right)\bigg|_{-1}^1 + \left(\dfrac{x^2}2-x\right)\bigg|_1^2 \\\\ = \left(\left(1-\frac12\right)-\left(-1-\frac12\right)\right) + \left(\left(2-2\right)-\left(\frac12-1\right)\right) \\\\ = \boxed{\frac52}$

5 0

2 years ago