What is step 10 in this proof

Julia has correctly answered 35 questions from a test, which is 7/12 of the total. How many questions did the test have?

otez555 [7]

Answer:

There are 60 questions on the test

Step-by-step explanation:

Hope this helps :)

4 0

3 years ago

188.49 rounded to the nearest 10th

Aleksandr-060686 [28]

Answer:

Step-by-step explanation:

188.5

3 0

3 years ago

Read 2 more answers

My brother wants to estimate the proportion of Canadians who own their house.What sample size should be obtained if he wants the

AVprozaik [17]

Answer:

a) $n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07$

And rounded up we have that n=1476

b) $n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681$

And rounded up we have that n=1681

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

If solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by $\alpha=1-0.9=0.1$ and $\alpha/2 =0.05$ . And the critical value would be given by:

$z_{\alpha/2}=\pm 1.64$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.02$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

And replacing into equation (b) the values from part a we got:

$n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07$

And rounded up we have that n=1476

Part b

For this case since we don't have a prior estimate we can use $\hat p =0.5$

$n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681$

And rounded up we have that n=1681

8 0

3 years ago

Clarita is a single taxpayer with two dependent children, ages 10 and 12. Clarita

lidiya [134]

Step-by-step explanation:

1. Clarita's total income =

Adjusted gross income (all from wages) + standard deduction

= $19,600 + $3,000 = $22,600 ( Actual spending is only $3,000 for two children)

According to USA (Pub.503.,)

you exclude or deduct dependent care benefits provided by a dependent care benefit plan, the total amount you exclude or deduct must be less than the dollar limit for qualifying expenses (generally, $3,000 if one qualifying person was cared for or $6,000 if two or more qualifying persons were cared for). (If two or more qualifying persons were cared for, the amount you exclude or deduct will always be less than the dollar limit because the total amount you can exclude or deduct is limited to $5,000.

2.Child and dependent care credit for 2019 is Zero

Because .,According to Income tax rules in USA (pub 501) "the deductions for personal and dependency exemptions for tax years 2018 through 2025 are suspended, and therefore, the amount of the deduction is zero. But in determining whether you may claim a person as a qualifying relative for 2019, the person's gross income must be less than $4,200, not zero."

Here Clarita's gross income is $22,600 ., more than $4,200

5 0

3 years ago

PLEASE HELP

Molodets [167]

B would be the correct answer

3 0

3 years ago