Answer:
(a^3)+b
Step-by-step explanation:
x^(2/5) + x^(1/5) + 1 = 3
subtract 3 from each side
x^(2/5) + x^(1/5) -2=0
let m = x^1/5
m^2 +m -2 =0
(m - 1) (m + 2) = 0
using the zero product property
m=1 m=-2
replace m = x^1/5
x^1/5 =1 and x^1/5 = -2
take everything to the 5th powr
x^ 1/5 ^ 5 = 1^5 and x^ 1/5 ^ 5 = -2 ^ 5
x = 1 and x = -32
Choice C
C. -32, 1
<u>Given</u><u> </u><u>:</u><u>-</u>
<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>
<u>Solution</u><u> </u><u>:</u><u>-</u>
Well there is no gain as you can see the CP > SP .So there is a loss . We can find the loss and loss% . As ,
Loss = CP - SP
Loss = $(6300-5000)= $1300
Now the loss% is ,
Loss% = Loss/CP * 100
Loss% = $1,300/$6300*100
Loss% = 13/63 * 100
Loss% = 20.63%
<u>Hence</u><u> the</u><u> </u><u>loss </u><u>is </u><u>$</u><u>1</u><u>3</u><u>0</u><u>0</u><u> </u><u>and </u><u>the </u><u>loss%</u><u> </u><u>is </u><u>2</u><u>0</u><u>.</u><u>6</u><u>3</u><u>%</u><u>.</u>
72 is dividable by 3. It is divisible by 3 because when you add 7 and 2, you get 9. According to the tests for divisibility, if the sum of the digits is divisible by 3, then the whole number is. 9 is divisible by 3, therefore 72 is as well.