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Anni [7]
3 years ago
6

What is the equivalent decimal for the fillowing:3/5

Mathematics
1 answer:
goldenfox [79]3 years ago
3 0
Decimal for 3/5= 6/10 = 0.6
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One horse can run 3/4 of a mile in 1.5 minutes. Another horse runs 2 1/4 miles in 4.5 minutes. assuming the horses run at a cons
BigorU [14]

Answer:

1/2

Step-by-step explanation:

30s = 1/4

30s=1/4

30s=1/4

8 0
2 years ago
What is the only function that allows us to pull the variable out of the exponent?​
Vilka [71]

Answer: isolate the exponent term on one side of the equation, and then apply the appropriate radical to both sides of the equation.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Can you help me get the answers
sergeinik [125]
The answer is b because your just adding and subtracting
7 0
3 years ago
Part A: The Sun produces 3.9 ⋅ 1033 ergs of radiant energy per second. How many ergs of radiant energy does the Sun produce in 3
Nuetrik [128]

5914 1404 393

Answer:

  A) 1.3×10^37 ergs

  B) 1.435×10^3 mm

Step-by-step explanation:

A) The amount of energy will be the product of the energy rate and time:

  (3.9×10^33 ergs/s)×(3.25×10^3 s) =12.675×10^(33+3) ergs

  = 1.2675×10^(1+36) ergs

  = 1.2675×10^37 ergs ≈ 1.3×10^37 ergs

The mantissa of the result is the product 3.9×3.25, adjusted to have one digit left of the decimal point. The exponent of the result is the sum of the exponents of the factors, adjusted by 1 to match the adjustment in the mantissa.

The final value should be rounded to 2 significant figures, reflecting the precision of the sun's energy production.

__

B) A millimeter is a small fraction of an inch. 10^-3 mm is a small fraction of the width of a human hair, so 1.435×10^-3 mm is not a reasonable estimate of the distance between railroad tracks.

On the other hand, 1.435×10^3 mm is 1.435 m, almost 56.5 inches. This is a much more reasonable measurement of the distance between railroad rails.

  1.435×10^3 mm is more reasonable

8 0
3 years ago
A room is 12m 15m long and 8m 91 cm broad .The floor of the room is tobe paved with squared tiles find the lenght of the largest
Nat2105 [25]

Answer:

81 cm

Step-by-step explanation:

Length of a room = 12m 15cm

Width of a room = 8 m 91 cm

12 m 15 cm = 1200 cm + 15 cm = 1215 cm

8 m 91 cm = 800 cm + 91 cm = 891 cm

The floor of the room is tobe paved with squared tiles. We need to find the length of the largest tile that can be used.

To find it we can find the HCF of 1215 cm and 891 cm.

Prime factorization of 1215 = 3 x 3 x 3 x 3 x 3 x 5

Prime factorization of 891 = 3 x 3 x 3 x 3 x 11

HCF = 3 x 3 x 3 x 3

= 81

Hence, the length of the largest tile that can be used is 81 cm.

5 0
3 years ago
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