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3 years ago

HELP PLEASE!!!!!!!!!!!!!!!

Mathematics

1 answer:

sukhopar [10]3 years ago

6 0

Answer:

Step-by-step explanation:

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Farrah is 4 years older than 5 times her brother Emil's age. Farrah is 19 years old. Let e represent Emil’s age. During the Stra

Pepsi [2]

The answer is B.
If Farrah is 5 times older than Emil plus 4 years, the equation would be 5e+4.

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3 years ago

Mario is missing half of his assignments. If a represents the number of assignments, write an expression to show how many assign

tekilochka [14]

You can't answer this you have no actual information. You don't know how many assignments there are.

a/2 would be the only possible answer

5 0

3 years ago

A 0.45-mm-wide slit is illuminated by light of wavelength 590 nm. What is the width (in mm) of the central maximum on a screen 1

Hitman42 [59]

Answer:

$w = \frac{2(590x10^{-9}) (1.5m)}{0.45x10^{-3}}=3.93 x10^{-3} m$

And if we convert this into mm we got:

$w= 3.93 x10^{-3} m *\frac{1000mm}{1 m}= 3.93 mm$

Step-by-step explanation:

For this case we have the following info givenL

$\lambda = 590 nm = 590 x10^{-9}m$ represent the wavelength

$s = 0.45 mm *\frac{1m}{1000 mm}= 0.45x10^{-3} m$ represent the width of the single slit

$L = 1.5 m$ represent the longitude

And we want to find the maximum width of the central maximum in mm, so we can use the following formula:

$w s = 2 \lambda L$

And if we solve for w the width we got:

$w = \frac{2\lambda L}{s}$

And replacing we got:

$w = \frac{2(590x10^{-9}) (1.5m)}{0.45x10^{-3}}=3.93 x10^{-3} m$

And if we convert this into mm we got:

$w= 3.93 x10^{-3} m *\frac{1000mm}{1 m}= 3.93 mm$

6 0

3 years ago

The distance traveled varies directly with the time spent in motion when speed is held constant. If d represents the distance tr

GrogVix [38]

We have a direct variation. Distance, D, varies directly as time, t.
So D = Kt where K is the constant. In this case, speed. So D = Kt is our constant of variation.
If D = 150 miles and t = 4 hours
Then we have 150 = K (4)
K = 150/4 = 37.5. The constant of variation is 37.5.
If you keep traveling at a constant speed K = 37.5 and D = 200. We have
200 = 37.5 * t
t = 200/37.5 = 5.333 hours.

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3 years ago

Prove that PQ + QR + RS + SP = 0 in the given quadrilateral<br>PQRS

Katarina [22]

Step-by-step explanation:

Using ∆ law of vector addition,

PR→=PQ→+QR→PR→=PQ→+QR→ - (i)

Also,

RP→=RS→+SP→RP→=RS→+SP→ - (ii)

Taking LHS,

=PQ→+QR→+RS→+SP→=PQ→+QR→+RS→+SP→

[Put value of PR→=PQ→+QR→PR→=PQ→+QR→ from equation (i) ]

=(PR→)+RS→+SP→=(PR→)+RS→+SP→

[Put value of RP→=RS→+SP→RP→=RS→+SP→ from equation (ii) ]

=PR→+RP→=PR→+RP→

=PR→−PR→=PR→−PR→

=0=0

RHS

7 0

3 years ago