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2 years ago

Volume with fractions 3 28 points

Mathematics

1 answer:

solniwko [45]2 years ago

6 0

Answer:

9 1/3 or 28/3 cm³

Step-by-step explanation:

Volume of rectangular prism is $Bh$ , where B = Area of the Base and h = height.

Area of the Base:

$2*\frac{7}{3}$
$\frac{14}{3}$

Area of Base x Height:

$\frac{14}{3} *2$
$28/3$ or $9 \frac{1}{3}$

Therefore, the answer is 28/3 or 9 1/3 cm³.

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Rectangle ABCD is shown to the right. Point E is located

mafiozo [28]

A) The area of the rectangle ABCD is base times height. 20in x 12in = 240 in sq.
B) The area of the triangle AED is base times height divided by two. (14in x 12in)/2 = 84in sq.
C) Figure EBCD is a right trapezoid (having one pair of parallel sides, while the others are slanted and forming a right angle).
D) Area of EBCD is the area of the rectangle minus the area of the triangle. 240in sq - 84in sq = 156in sq.

4 0

2 years ago

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igomit [66]

Answer:

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Step-by-step explanation:

Statistics is a branch of mathematics that deals with collecting, analyzing, and interpreting information

6 0

3 years ago

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How do I do this in Standard form

jasenka [17]

The equation is already in Standard Form.

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5 0

3 years ago

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PLEASE HELP WITH BOTH WILL CROWN BRAINLIEST !!!!

Korvikt [17]

41) you have a 40 day period
two visits with +75 centimeter growth each
3 visits with +6 each
in total 2*75+3*6=150+18=168
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42)
7x total
3x20
2x15
1x13
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if you order these into a list:
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3 0

3 years ago

g In R simulate a sample of size 20 from a normal distribution with mean µ = 50 and standard deviation σ = 6. Hint: Use rnorm(20

Illusion [34]

Answer:

> a<-rnorm(20,50,6)

> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

Then we can find the mean and the standard deviation with the following formulas:

> mean(a)

[1] 50.72451

> sqrt(var(a))

[1] 7.470221

Step-by-step explanation:

For this case first we need to create the sample of size 20 for the following distribution:

$X\sim N(\mu = 50, \sigma =6)$

And we can use the following code: rnorm(20,50,6) and we got this output:

> a<-rnorm(20,50,6)

> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

Then we can find the mean and the standard deviation with the following formulas:

> mean(a)

[1] 50.72451

> sqrt(var(a))

[1] 7.470221

5 0

3 years ago