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2 years ago

What is the are of this figure giving our brainlist to whoever writes the answer in 10 min

Mathematics

1 answer:

kiruha [24]2 years ago

6 0

Answer:

63 cm^2

Step-by-step explanation:

For finding the area, split the given figure into 2 rectangles one with dimensions 6×5 and another with dimensions 12×2

Area = 6×5 + 12×2 = 39+24 = 63

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Find three consecutive odd integers so that the product of the second and third integer is 63

Doss [256]

<span>product of the second and third integer is 63
63=3*3*7
or
63=7*9 These are two consecutive integers.
We need three integers and the first one is missing so the solution:
5-7-9

</span>

4 0

3 years ago

Which statements describe a triangular prism? Select three options. It has one base. It has two bases. It has three lateral face

oksian1 [2.3K]

The statements that describe a triangular prism are:

It has one base.
It has three lateral faces.
Its lateral faces are rectangular.

<h3>What is a triangular prism?
</h3>

A triangular prism is a three-dimensional object that is made up of one base that has the shape of a triangle and three lateral sides that have the shape of a rectangle. A triangular prism has 5 faces, 9 edges and 6 vertices.

To learn more about prisms, please check: brainly.com/question/13048128

#SPJ1

3 0

1 year ago

5) Choose which postulate proves the triangles congruent.

LuckyWell [14K]

Answer:

AAS

Step-by-step explanation:

HEHE

5 0

2 years ago

Find the length of the arc of the circular helix with vector equation r(t) = 2 cos t i + 2 sin t j + tk from the point (2, 0, 0)

USPshnik [31]

$\vec r(t)=2\cos t\,\vec\imath+2\sin t\,\vec\jmath+t\,\vec k$

$\implies\vec r'(t)=-2\sin t\,\vec\imath+2\cos t\,\vec\jmath+\vec k$

$\implies\|\vec r'(t)\|=\sqrt{(-2\sin t)^2+(2\cos t)^2+1^2}=\sqrt5$

Then the length of the arc is

$\displaystyle\int_0^{2\pi}\|\vec r'(t)\|\,\mathrm dt=\sqrt5\int_0^{2\pi}\mathrm dt=2\sqrt5\,\pi$

4 0

3 years ago

What is the average (arithmetic mean) of the first 90 measurements in a certain list of 92 measurements? (1) the average of the

marishachu [46]

The sum of all the measurements is just the average times the number.

$\bar x = \frac{1}{n} \sum_{i=1}^n x_i$

$\sum_{i=1}^n x_i = n \bar x$

So if the average of all 92 is 7 the sum of those is $92 \times 7$

The average of the last two is 7.2 so their sum is $2 \times 7.2$

That means the sum of the first 90 is $92 \times 7 - 2 \times 7.2$

so the average of the first 90 is

$\dfrac{92 \times 7 - 2 \times 7.2}{90} = 6.99556$ cm

7 0

3 years ago