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vagabundo [1.1K]
3 years ago
15

Please answer this please

Mathematics
1 answer:
cluponka [151]3 years ago
4 0

Step-by-step explanation:

<h3>1. x² + 4 = (x+2)² </h3>

<h3> : x² + 4 = x² + 4 (Yes)</h3>

<h3>2. (2x+6)²= 4(x+3)²</h3>

<h3> : 4x²+36 = 4x² + 36 ( Yes)</h3>

<h3>3. (x-3)(x-3)= (x-9)² (NO)</h3>

<h3>beacause , True statement is</h3><h3> (x+3)(x-3)= (x-9)²</h3>

<h3>4. x²-10x+25 = (x-5)(x+5) (No)</h3>

<h3> : x²-2x+y² = (a-b)(a+b) </h3>

<h3>Therefore, its not true statement!</h3>
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pantera1 [17]

Answer:

400 in²

Step-by-step explanation:

(20×16) + (½×8×20)

320 + 80 = 400 in²

8 0
3 years ago
Can anyone share the process please? ​
gtnhenbr [62]

Answer:

3x³ + x² + x + 1

= 3x³ - 3x² + 4x² - 4x + 5x - 5 + 6

= 3x²(x - 1) + 4x(x - 1) + 5(x - 1) + 6

= (x - 1)(3x² + 4x + 5) + 6

but 3x³ + x² + x + 1 = (x - 1).Q(x) + R

=> Q(x) = 3x² + 4x + 5

R = 6

4 0
3 years ago
The difference of the square of a number and 4 is equal to 3 times that number. Find the negative solution.
leonid [27]

The negative solution is x = –1.

Solution:

Let the number be x.

Square of a number = x²

3 times a number = 3x

Difference of square of a number and 4 = 3 times that number

\Rightarrow x^2-4=3x

Subtract 3x from both sides of the equation, we get

\Rightarrow x^2-3x-4=0

–3x can be written as x – 4x.

\Rightarrow x^2+x-4x-4=0

\Rightarrow( x^2+x)+(-4x-4)=0

1st bracket have common term x and bracket have –4 common term.

\Rightarrow x( x+1)-4(x+1)=0

Take common term x + 1 outside.

(x+1)(x-4)=0

<em>By zero factor principle, if AB = 0 then A = 0 or B = 0.</em>

x + 1 = 0,   x – 4 = 0

x = –1,   x = 4

The negative solution is x = –1.

7 0
4 years ago
The temperature at noon at a ski resort is 3 F . The temperature drops 8 F by midnight what is the temperature at midnight
DIA [1.3K]

Answer:

-5

Step-by-step explanation:

3 minus 8 equals -5

(20 characters needed)

4 0
3 years ago
Read 2 more answers
V = u + at <br> u = 2 and a= -5 and t= 1/2<br> work out the value of v
Darina [25.2K]

Step-by-step explanation:

v=u+at

v=2+(-5)<u>1</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>2

v=2-2.5

v=-0.5m/s²

hope it helps.

8 0
3 years ago
Read 2 more answers
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