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denis-greek [22]
3 years ago
13

Write on equation if the slope is 3/4 and the y-intercept is -4,

Mathematics
2 answers:
KonstantinChe [14]3 years ago
7 0

Answer:

thw abswer os tywentr yaxel

Step-by-step explanation:

Alja [10]3 years ago
5 0

Answer:

y = 3/4x + -4

or y = 3/4x - 4

Step-by-step explanation:

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R=26 in. find the diameter.
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Answer:

see

Step-by-step explanation:

diameter=2×pi×r

diameter. 2.22/7.r

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3 years ago
LMN and QRS are similar. Find the value of X.​
Trava [24]

x+5/30 = 50/75

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Maggie has $14,100 to invest, and wishes to gain $4,000 in interest over the next eight years. Approximately what is the minimum
julsineya [31]
Simple interest doesn't compound, so we just find the interest she needs by dividing 4,000 by 8, and then divide that number by her principal to find the rate of interest. 

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3 0
3 years ago
Suppose you cool a pot of soup in a 20°C room. Right when you take the soup off the stove, you measure its temperature to be 180
dezoksy [38]

Answer:

  • 28.3 minutes
  • 53.6°C

Step-by-step explanation:

The temperature of the soup is described by Newton's Law of Cooling, which says the rate of change of temperature is proportional to the difference between the temperatures of the soup and the room. The solution to this differential equation is the exponential function ...

  f(t) = a +b·c^(t/τ)

where a is the room temperature, b is the initial difference in temperature, and c is the fractional change in the difference in temperature over time period τ.

__

<h3>application</h3>

For the given scenario, we find ...

  a = room temperature = 20 . . . . degrees C

  b = (180 -20) = 160 . . . . degrees C

  c = (100 -20)/(180 -20) = 80/160 = 1/2 . . . . in τ = 20 minutes

So, the formula for the temperature of the soup is ...

  f(t) = 20 +160(1/2)^(t/20) . . . . . . . degrees C after t minutes

__

<h3>time to 80°C</h3>

Solving for t when f(t) = 80, we find ...

  80 = 20 +160(1/2)^(t/20)

  3/8 = (1/2)^(t/20) . . . . . subtract 20, divide by 160

  20×log(3/8)/log(1/2) = t ≈ 28.3 . . . take logarithms, divide by coefficient of t

It will take about 28.3 minutes to cool to 80°C.

__

<h3>temp at 45 minutes</h3>

The temperature after 45 minutes is ...

  f(45) = 20 +160(1/2)^(45/20)

  f(45) ≈ 53.6 . . . . degrees C

After 45 minutes the temperature of the soup will be about 53.6°C.

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