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Delvig [45]
2 years ago
8

Anton bakes 36 cookies. He gives cookies to each of his 3 friends.

Mathematics
2 answers:
AVprozaik [17]2 years ago
8 0

36 - 3c

<u>This</u><u> is</u><u> your</u><u> </u><u>answer</u>

Because 3c is given cookies and 36 minus baked cookies can give value of total cookies

taurus [48]2 years ago
3 0

Answer:

36-3c shows how many cookies Anton has left .

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3 years ago
Someone please help I’ve been spamming on this and no one has helped yet so please
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Answer:

The value of x would 12.2.

Step-by-step explanation:

You have to use the pythagorean theorem to solve this.

a = 5.85 (11.7/2)

b = what we are trying to find

c = 13.5

\sqrt{13.5^{2} - 5.85^{2}  } = 12.1666 which rounds to 12.2

I hope this helps, I apologize if it isn't right.

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3 years ago
Consider a game in which players roll a number cube to determine the number of points earned. If a player rolls a prime number,
Aleksandr-060686 [28]

Answer:

The expected value of the points earned on a single roll in this game is \dfrac{1}{6} = 0.1667 .

Step-by-step explanation:

We are given that consider a game in which players roll a number cube to determine the number of points earned. If a player rolls a prime number, that many points will be added to the player’s total. Any other roll will be deducted from the player’s total.

Assuming that the numbered cube is a dice with numbers (1, 2, 3, 4, 5, and 6).

Here, the prime numbers are = 1, 2, 3 and 5

Numbers which are not prime = 4 and 6

This means that if the dice got the number 1, 2, 3 or 5, then that many points will be added to the player’s total and if the dice got the number 4 or 6, then that many points will get deducted from the player’s total.

Here, we have to make a probability distribution to find the expected value of the points earned on a single roll in this game.

Note that the probability of getting any of the specific number on the dice is   \dfrac{1}{6} .

      Numbers on the dice (X)                       P(X)

                      +1                                                 \frac{1}{6}

                      +2                                                \frac{1}{6}

                      +3                                                \frac{1}{6}

                      -4                                                 \frac{1}{6}

                      +5                                                \frac{1}{6}

                      -6                                                 \frac{1}{6}

Here (+) sign represent the addition in the player's total and (-) sign represents the deduction in the player's total.

Now, the expected value of X, E(X)  =  \sum X \times P(X)

   =  (+1) \times \frac{1}{6} +(+2) \times \frac{1}{6} +(+3) \times \frac{1}{6} +(-4) \times \frac{1}{6} +(+5) \times \frac{1}{6} +(-6) \times \frac{1}{6}

   =  \frac{1}{6} + \frac{2}{6} + \frac{3}{6} - \frac{4}{6} + \frac{5}{6} - \frac{6}{6}

   =  \frac{1+2+3-4+5-6}{6}

   =  \frac{11-10}{6}= \frac{1}{6}

Hence, the expected value of the points earned on a single roll in this game is  \frac{1}{6} = 0.1667 .

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Answer:

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Step-by-step explanation:

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