Answer:
Step-by-step explanation:
Given that three airlines serve a small town in Ohio. Airline A has 52% of all scheduled flights, airline B has 27% and airline C has the remaining 21%.
Their on-time rates are 83%, 66%, and 36%, respectively.
Airlines A B C
Flights 52% 27% 21% 100%
On time rates 83% 66% 36%
Flight*online rates 43.1600% 17.8200% 7.5600% 68.5400%
Thus the above table shows the product of no of flights and on time rates.
Prob it was airline A given it left on time
=
ACB + BAC =90
ACB + 37 = 90
ACB = 53
Tan (53) = 10/x
X= 7.536
(Hope this helped have a great day)
Answer:
5.5, 9.5
Step-by-step explanation:
Let x and y be the numbers
x+y = 15
x-y = 4
Add the two equations together to eliminate y
x+y = 15
x-y = 4
------------------
2x = 19
Divide by 2
2x/2 =19/2
x = 9.5
Now find y
x+y = 15
9.5+y = 15
Subtract 9.5
x = 15-9.5
x =5.5