Question

On a coordinate plane, a dashed straight line has a positive slope and goes through (negative 3, 1) and (0, 3). Everything to the left of the line is shaded.
Which linear inequality is represented by the graph?

Answer 1

Answer:

the correct answer is y>2x+(3/4) and (2,5)

hope this helps

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Step-by-step explanation:

I just took the test on E2020

Answer 2

Answer:

$y> \frac{2}{3}x+3$

Step-by-step explanation:

we have the points

(-3,1) and (0,3)

step 1

Find the slope m of the line

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the values

$m=\frac{3-1}{0+3}$

$m=\frac{2}{3}$

step 2

Find the equation of the line in slope intercept form

$y=mx+b$

we have

$m=\frac{2}{3}$

$b=3$ ----> the y-intercept is the point (0,3)

substitute the values

$y=\frac{2}{3}x+3$

step 3

Find the equation of the inequality

we know that

The slope is positive

Everything to the left of the line is shaded ( The inequality is of the form y > ax+b or y ≥ ax+b)

Is a dashed line (The inequality is of the form y > ax+ b or y < ax+b)

therefore

The equation of the inequality is of the form y > ax+b

The inequality is

$y> \frac{2}{3}x+3$

see the attached figure to better understand the problem