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Mariana [72]
2 years ago
8

Please help will give brainliest

Mathematics
1 answer:
Sergeeva-Olga [200]2 years ago
5 0
The answer is below
Let me know if it is right

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What is the perimeter of this rectangle?
garik1379 [7]

Answer:

B.) (X2 -x1)(y2 - y1

Step-by-step explanation:

I learned the formula

7 0
3 years ago
The product of 2 √3 and 3 √12 simplified form is...
Serjik [45]
<h2>Greetings!</h2><h3>When multiplying two roots together, you can rearrange the equation so that the roots are next to each other and so are the whole numbers:</h3>

2 x 3 x \sqrt{3} x \sqrt{12}

<h3>This means that 2 x 3 is simple, = 6,</h3><h3>But when multiplying \sqrt{3} x \sqrt{12} you simply multply the two numbers and put them in a square root:</h3>

\sqrt{3} x \sqrt{12} = \sqrt{36}

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2 x 3 x 6 = 36

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3 0
3 years ago
Show 2-(-3) on a number line.
9966 [12]
Just put a closed circle above 5 on the # line.
3 0
3 years ago
If an object is launched at an angle of 28° with an initial velocity of 133 ft./s from a height of 6 feet how many seconds will
Tema [17]

Answer:

Hence after  3.98 sec  i.e  4 sec Object will hit the ground  .

Step-by-step explanation:

Given:

Height= 6 feet

Angle =28 degrees.

V=133 ft/sec

To Find:

Time in seconds after which it will hit the ground?

Solution:

<em>This problem is related to projectile motion for objec</em>t

First calculate the Range for object  and it is given by ,

R=v^2Sin(2Ф)/g

Here R= range  g= acceleration due to gravity =9.8 m/sec^2

1m =3.2 feet

So 9.8 m, equals to 9.8 *3.2=31.36 ft

So g=31.36 ft/sec^2. and 2Ф=2(28)=56

R=133^2*Sin(56)/31.36

R=14664.84/31.36

R=467.62  fts

Now using Formula for time and range as

R=VxT

Vx is horizontal velocity

Vx=V*cosФ

Vx=133*cos(28)

Vx=117.43  ft/sec

So above equation becomes as ,

467.62=117.43*T

T=467.62/117.43

T=3.98 sec

T is approximately equals to 4 sec.

4 0
3 years ago
How do I do this? Please help me
AnnyKZ [126]
You divide 46 by 5.2 and the answer should be 8.8 inches.
7 0
3 years ago
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