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3 years ago

A figure is shown. 157.3° What is the measure, in degrees, of angle x?

Mathematics

1 answer:

Mandarinka [93]3 years ago

7 0

It is on a straight line which is equal to 180• so 189 -157.3 = 22.7•

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The notation f:S→T denotes that f is a function, also called a map , defined on all of a set S and whose outputs lie in a set T

AnnyKZ [126]

Answer:

There are many. Two examples are

$f(x) = x, \\f(x) = x^3$

Step-by-step explanation:

There are many examples. The simplest is

1 -

$f(x) = x$

It is trivial that

$\text{if \,\,\,\,} f(x) = f(y) \,\,\,\,\,\text{then} \,\,\,\,\, x=y$

2 -

$f(x) = x^3$

That function is injective as well.

$\text{if \,\,\,\,} x^3 = y^3 \,\,\,\,\,\text{then} \,\,\,\,\, x=y$

An example of a function that is NOT injective is

$f(x) = x^2$

Notice that

$f(-2) = (-2)^2 = 2^2 = 4$

4 0

3 years ago

Given: F(x) = 2x - 1; G(x) = 3x + 2; H(x) = x 2<br><br> Find F{G[H(2)]}

Tamiku [17]

H(2)=x²=2²=4
G[H(2)]=G(4)=3(4)+2=12+2=14
F[G[H(2)]]=F(14)=2(14)-1=28-1=27

Answer: F[G[H(2)]]=27

4 0

3 years ago

Read 2 more answers

Find the percent of change if the original price is $246.95 and the new price is $199.95. Round to nearest tenth of a percent if

Grace [21]

Answer:

<h3>Percentage change = 19%</h3>

Step-by-step explanation:

Since the new price is lesser than the original price the percentage change will be a decrease.

To find the percentage change use the formula

$Percentage \: \: change = \frac{change}{original \: \: quantity} \times 100$

To find the change subtract the new price from the original price

new price = $199.95

original price = $246.95

Change = $246.95 - $ 199.95 = $47

$Percentage \: \: change = \frac{47}{246.95} \times 100$

<h3>Percentage change = 19%</h3>

Hope this helps you

3 0

3 years ago

Read 2 more answers

What is 4 percent of 3/5?

Thepotemich [5.8K]

.024

.4 divided by 3/5 equals .024.

5 0

3 years ago

Read 2 more answers

In April 1974, Steve Prefontaine completed a 10 km race in a time of 27 min, 43.6 s. Suppose "Pre" was at the 7.15 km mark at a

ELEN [110]

Answer:

0.2583 m/s²

Step-by-step explanation:

The relationship between speed, distance, and time is ...

speed = distance/time

Of course, the relationship between the various units of measure is ...

1 km = 1000 m
1 min = 60 s

The average speed for the first 7.15 km was ...

(7150 m)/(1500 s) = 4 23/30 m/s

The acceleration is considered to be uniform over the 60-second period. The distance traveled during that time will be the same as the distance traveled at the initial speed for 30 s plus that traveled at the final speed for 30 s. That is, we can compute the final speed as though "Pre" ran 25.5 minutes (1530 s) at his initial speed and the remaining time (133.6 s) at his final speed.

The distance for 25.5 minutes at 4 23/30 m/s is ...

(1530 s)(143/30 m/s) = 7293 m

The remaining distance is then ...

10,000 -7,293 = 2,707 . . . meters

And the final speed is ...

(2707 m)/(133.6 s) ≈ 20.262 m/s

The acceleration is the change in speed divided by the time period:

(20.262 m/s -4.767 m/s)/(60 s) ≈ 0.2583 m/s²

_____

<em>Comment on these numbers</em>

According to this scenario, Pre's speed for the last 2000 meters, sustained for more than a minute, was more than 20 m/s -- about <em>double the world record</em> speed for a 100 meter sprint. It was a little more than <em>4 times</em> his speed for the first 25 minutes.

5 0

3 years ago