3 years ago

Help me please I need this now

Mathematics

1 answer:

puteri [66]3 years ago

4 0

192!
you do length times width times height
hope this helps

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Solve similar triangles (advanced)

Eddi Din [679]

Triangles ABC and ADE are similar, meaning that
AB/BC=AD/DE
6/5=(6+x)/14
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X=10.8
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2 years ago

dirk sold 7 more than 2 times as many gym memberships this month than last month. the month he sold 43 memberships. how many mem

jenyasd209 [6]

Answer:

Step-by-step explanation:

x = last month

y = this month

y = 2x + 7

y = 43

43 = 2x + 7

43 - 7 = 2x

36 = 2x

36/2 = x

18 = x <== he sold 18 gym memberships last month

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3 years ago

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antiseptic1488 [7]

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3 years ago

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The angle θ 1 is located in Quadrant IV, and cos ⁡ ( θ 1 ) = 9/ 19 , theta, start subscript, 1, end subscript, right parenthesis

Firdavs [7]

Answer:

$sin\theta_1 = - \frac{2\sqrt{70}}{19}$

Step-by-step explanation:

We are given that $\theta_1$ is in fourth quadrant.

$cos\theta_1$ is always positive in 4th quadrant and

$sin\theta_1$ is always negative in 4th quadrant.

Also, we know the following identity about $sin\theta$ and $cos\theta$ :

$sin^2\theta + cos^2\theta = 1$

Using \theta_1 in place of \theta:

$sin^2\theta_1 + cos^2\theta_1 = 1$

We are given that $cos\theta_1 = \frac{9}{19}$

$\Rightarrow sin^2\theta_1 + \dfrac{9^2}{19^2} = 1\\\Rightarrow sin^2\theta_1 = 1 - \dfrac{81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{361-81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{280}{361}\\\Rightarrow sin\theta_1 = \sqrt{\dfrac{280}{361}}\\\Rightarrow sin\theta_1 = +\dfrac{2\sqrt{70}}{19}, -\dfrac{2\sqrt{70}}{19}$

$\theta_1$ is in 4th quadrant so $sin\theta_1$ is negative.

So, value of $sin\theta_1 = - \frac{2\sqrt{70}}{19}$

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2 years ago

Divide. 3/5 ÷ 1 1/4 A.) 1/4 B.) 12/25 C.) 3/4 D.) 2 2/5

daser333 [38]

Answer:

the answeer is d i got it right

Step-by-step explanation:

no need it d

6 0

2 years ago