Answer:
Quadrant one if its positive (6, 8)
Complete question:
y = 2x² + 2x - 3
x = -2 -1 0 1 2
Answer:
<u>Complete table of values</u>
x: -2 -1 0 1 2
y: 1 -3 -3 1 9
Step-by-step explanation:
Given;
y = 2x² + 2x - 3
To complete the table of values of the equation above, we substitute the value of x into the given equation and solve for y.
when, x = -2
y = 2(-2)² + 2(-2) - 3
y = 8 - 4 - 3
y = 1
when x = -1
y = 2(-1)² + 2(-1) - 3
y = 2 - 2 - 3
y = -3
when x = 0
y = 2(0)² + 2(0) - 3
y = 0 - 0 - 3
y = -3
when x = 1
y = 2(1)² + 2(1) - 3
y = 2 + 2 - 3
y = 1
when x = 2
y = 2(2)² + 2(2) - 3
y = 8 + 4 - 3
y = 9
<u>Complete table</u>
x: -2 -1 0 1 2
y: 1 -3 -3 1 9
Im imperfect linear :( line grafh
Answer:
y = 2x
the formula for linear equations are y = mx+c,
where m is the gradient,
and c is the y-intercept
to find m (the gradient):
1. pick to points on the graph (eg. -2,-4 and 2,4)
2 substitute the values into the formula for gradient y2-y1/x2-x1.
m = y2-y1/x1-x2
= -4 -4/-2-2
= -8/-4
= 2
to find c (y-intercept):
- the y-intercept is where the graph cuts the y axis
- in this graph, the y-intercept is 0
hence,
c = 0
substitute m = 2 and c = 0 to y = mx+c,
y = 2x + 0
y = 2x
hence, the equation that best represents the relationship shown in the graph is y = 2x.