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Andrej [43]
3 years ago
5

A ball is released at the top of a ramp at t = 0. Which is the speed of the ball at t = 4?

Physics
1 answer:
Kruka [31]3 years ago
5 0

Answer:

For uniform acceleration

a = (v2 - v1) /t = 2.5      acceleration is constant 2.5

v2 = 2.5 * 4         v1 = 0 at t = 0

v2 = 2.5 m/s^2 * 4 s = 10 m/s

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This is called an organ.  Examples of organs are: your heart, brain, lungs, liver, stomach etc.
4 0
4 years ago
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The Bohr model of the hydrogen atom pictures the electron as a tiny particle moving in a circular orbit about a stationary proto
igor_vitrenko [27]

a) The angular velocity of the electron is 4.12\cdot 10^{16} rad/s

b) The number of revolutions per second is 6.54\cdot 10^{15} rev/s

c) The centripetal acceleration of the electron is 8.98\cdot 10^{22} m/s^2

Explanation:

a)

This is a problem of uniform circular motion: in fact, the electron orbits around the proton in a uniform circular motion.

The angular velocity of an object in uniform circular motion is given by

\omega = \frac{v}{r}

where

v is the linear speed

r is the radius of the trajectory

For the electron orbiting around the proton, we have

v=2.18 \cdot 10^6 m/s

r=5.29\cdot 10^{-11} m

Therefore, the angular velocity is

\omega=\frac{2.18\cdot 10^6}{5.29\cdot 10^{-11}}=4.12\cdot 10^{16} rad/s

b)

The period of revolution of the electron is given by

T=\frac{2\pi}{\omega}

where

\omega = 4.12\cdot 10^{16}rad/s is the angular velocity

Substituting,

T=\frac{2\pi}{4.12\cdot 10^{16}}=1.53\cdot 10^{-16}s

The period is the time the electron takes to make one complete orbit around the proton; therefore, the number of revolutions of the electrons in one second is:

f=\frac{1}{T}=\frac{1}{1.53\cdot 10^{-16}}=6.54\cdot 10^{15} rev/s

c)

The centripetal acceleration of an object in circular motion is

a=\frac{v^2}{r}

where

v is the linear speed

r is the radius of the circle

For the electron, we have

v=2.18 \cdot 10^6 m/s

r=5.29\cdot 10^{-11} m

Therefore, the centripetal acceleration is

a=\frac{(2.18\cdot 10^6)^2}{5.29\cdot 10^{-11}}=8.98\cdot 10^{22} m/s^2

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

7 0
4 years ago
The mechanical advantage of a simple machine is 3 and its velocity ratio is 4 find its efficiency ​
LiRa [457]

Answer:

75%

Explanation:

Efficiency=MA/VR*100

=3/4*100

=0.75*100

=75%

6 0
2 years ago
23. A pogo stick has a spring with a force constant of 2.50×104N/m , which can be compressed 12.0 cm. To what maximum height can
tensa zangetsu [6.8K]

Answer:

The maximum height the child can jump on the stick

h=0.459m

Explanation:

Energy conservation

Energy kinetic = Work

The energy the child do get the height jump is proportional at the distance and the consta can be compressed so:

\frac{1}{2}*k*x^{2} =m*g*h\\k=2.50x10^{4} \frac{N}{m}\\x=12cm*\frac{1m}{100cm}=0.12m\\h=\frac{k*x^{2} }{2*m*g}\\h=\frac{2.50x10^{4}\frac{N}{m}*(0.12m)^{2} }{2*40kg*9.8\frac{m}{s^{2}}}\\h=\frac{360\frac{N}{m}m^{2} }{784N}\\h=0.459m

8 0
4 years ago
Pls answer!! 20 points and will give crown to best answer!!
docker41 [41]
I am 99999.999999999% sure that it is his second law of motion. 

Hope this helped! :) Please mark brainliest 
5 0
4 years ago
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