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son4ous [18]
3 years ago
11

HELP IM TIMED. ILL MARK BRAINLIEST PLSSSSSS.

Physics
1 answer:
Alex17521 [72]3 years ago
5 0

Answer:

According to Newton's Second Law of Motion :    

Where,

F = Force Applied

m = Mass of the object

a = Acceleration

Now, we will use this law to solve this question.

Given :

Acceleration or a = 15.3 m/s²

Force = 44 N

Mass = ?

Substitute, the given values in the formula.

F = ma

⇒ m = F/a

   m = 44/15.3

<u>m = 2.9 kg</u>

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A man walks 30 m to the west, then 5 m to the east in 45 seconds. What is his average speed?
dsp73

The average speed is  0.55 m/s

<h3>What was his displacement?</h3>

Displacement is defined as the change in position of an object.

Mathematically,

D = Initial value - Final Value

D = 30 - 5 = 25m

Now , We have to find the average velocity,

Average velocity is calculated by the formula V = D/t,

where V equals the average velocity, D equals total displacement and t equals total time.

V = D/t

V = 25 m / 45s

V = 0.55 m/s

So , The average speed is o.55 m/s

learn more about average speed:brainly.com/question/9834403

#SPJ1

5 0
2 years ago
In the produce section of a supermarket, five pears are placed on a spring scale. The placement of the pears stretches the sprin
tankabanditka [31]

Answer:

The displacement of the spring due to weight is 0.043 m

Explanation:

Given :

Mass m = 2 Kg

Spring constant k = 450 \frac{N}{m}

According to the hooke's law,

  F = -kx

Where F = force, x = displacement

Here,

F = mg         ( g = 9.8 \frac{m}{s^{2} } )

F = 2 \times 9.8 = 19.6 N

Now for finding displacement,

  x = \frac{F}{k}

Here minus sign only represent the direction so we take magnitude of it.

  x = \frac{19.6}{450}

  x = 0.043 m

Therefore, the displacement of the spring due to weight is 0.043 m

8 0
4 years ago
Suppose that in a lightning flash the potential difference between a cloud and the ground is 1.3×109 V and the quantity of charg
Georgia [21]

Answer:

A) ΔU = 3.9 × 10^(10) J

B) v = 8420.75 m/s

Explanation:

We are given;

Potential Difference; V = 1.3 × 10^(9) V

Charge; Q = 30 C

A) Formula for change in energy of transferred charge is given as;

ΔU = QV

Plugging in the relevant values gives;

ΔU = 30 × 1.3 × 10^(9)

ΔU = 3.9 × 10^(10) J

B) We are told that this energy gotten above is used to accelerate a 1100 kg car from rest.

This means that the initial potential energy will be equal to the final kinetic energy since all the potential energy will be converted to kinetic energy.

Thus;

P.E = K.E

ΔU = ½mv²

Where v is final velocity.

Plugging in the relevant values;

3.9 × 10^(10) = ½ × 1100 × v²

v² = [7.8 × 10^(8)]/11

v² = 70909090.9090909

v = √70909090.9090909

v = 8420.75 m/s

4 0
3 years ago
Question 1
sineoko [7]
Velocity = displacement / time
Displacement = 2.3 km
Time = 5.78 mins
Velocity = 2.3/5.78
Velocity = 0.398 to the nearest 3 significant figures
4 0
3 years ago
Which of these would have a volume equal to about 2 cm³?
postnew [5]
Answer could be2 grains of rice
5 0
3 years ago
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