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3 years ago

crabbe eat 12 minutes in 2.4 minutes. goyle eats 20 cupcake in 3.4 minutes. who eats cupcake at a faster rate

Mathematics

1 answer:

malfutka [58]3 years ago

5 0

Answer:

crabbe eats the cupcake at a faster rate

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Find the 96th term of the arithmetic sequence 1, -12, -25, ...

goldenfox [79]

Answer:

The 96th term of the arithmetic sequence is -1234.

Step-by-step explanation:

first term (a)=1

second term (t2)=-12

common difference (d)= t2-a

d=-12-1

d=-13

96th term (t96)=?

We know that,

t96=a+(n-1)d

t96=1+(96-1)(-13)

t96=1+95(-13)

t96=1-1235

t96=-1234

6 0

3 years ago

4.16 X 10 to the 3rd power

horsena [70]

Answer:

4,160

Step-by-step explanation:

your welcome

8 0

3 years ago

Which statement best compares the two functions?

podryga [215]

Answer:

A) Neither function A nor function B has an x-intercept.

Step-by-step explanation:

3 0

3 years ago

Help please. with the steps on image.

Kipish [7]

Answer:

T(n) = 3n² - 4
-189 doesn't belong

Step-by-step explanation:

Given sequence:

-1, 8, 23, 44, 71

The first differences:

9, 15, 21, 27

The second differences:

6, 6, 6

If the sequence is T(n) = an² + bn + c, we have:

2a = 6 ⇒ a = 3

Using the first and second differences work out the value of zero term:

9 - 6 = 3
-1 - 3 = -4

This gives us c = - 4

Now we have:

T(n) = 3n² + bn - 4

The first term is T(1) = -1, substitute n = 1 and find the value of b:

3(1²) + b*1 - 4 = - 1
3 + b - 4 = - 1
b = 0

The nth term is:

T(n) = 3n² - 4

Now lets find if -189 belongs to this sequence:

- 189 = 3n² - 4
3n² = - 185

The left side is positive and the right side is negative so the answer is also negative

5 0

3 years ago

Solve using the quadratic formula. Show all work. Write each solution in simplest form. No decimals.

lawyer [7]

Given:

The quadratic equation is:

$12a^2+9a+7=0$

To find:

The solution of the given equation in simplest form by using the quadratic formula.

Solution:

If a quadratic equation is $ax^2+bx+c=0$ , then the quadratic formula is:

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

We have,

$12a^2+9a+7=0$

Here, $a=12,b=9,c=7$ . Using the quadratic formula, we get

$x=\dfrac{-(9)\pm \sqrt{(9)^2-4(12)(7)}}{2(12)}$

$x=\dfrac{-9\pm \sqrt{81-336}}{24}$

$x=\dfrac{-9\pm \sqrt{-255}}{24}$

$x=\dfrac{-9\pm i\sqrt{255}}{24}$ $[\because \sqrt{-a}=i\sqrt{a}]$

The solutions of the given equations are $x=\dfrac{-9-i\sqrt{255}}{24}$ and $x=\dfrac{-9+i\sqrt{255}}{24}$ .

Therefore, the correct option is B.

8 0

3 years ago