Question 1: If shes making 4 hats alone and then Quadruples it shes making 16 hats per week if she quadruples it again she will be knitting 64 hats per week.
4x4=16
16x4=64hats
Question 2: There is an error because 5x5x5 = 5³
Question 3: 2⁴ - 8 x 2 / 4 = 12
2⁴ = 16 - 8 x 2 / 4
8x2 = 16
16/4 = 4
16-4 = 12
Yes. If the segment only has 2 points, it can be named both ways.
Answer:
f(g(2)) = 102
Step-by-step explanation:
f(x) and f(g(2))
As we can see, we can find g(2) and substitute this value into
f(x)=x² + 2x + 3 instead of x.
g(x) = x² + 5, g(2) = 2² + 5 = 9
f(x)=x² + 2x + 3
f(9)=9² + 2*9 + 3= 102
We know that
1) Sandra can run a mile in 6 minutes-------> 6*60-----> 360 sec
2) 4 laps around the track equals 1 mile
so
4 laps around the track in 360 sec
1 lap in 360/4--------> 90 sec
3) the position of Sandra for t=90 sec must be equal to the point S (0,56)
I proceed to analyze each case for t=90 sec
case a) x(t)=-140 cos(pi*t/45) y(t)=112 sin(pi*t/45)
x(t)=-140 cos(pi*90/45)------> -140
y(t)=112 sin(pi*90/45)-------> 0
the position is the point (-140,0)------> is not the point S
case b) x(t)=140 sin(pi*t/90) y(t)=-112 cos(pi*t/90)
x(t)=140 sin(pi*90/90)------> 0
y(t)=-112 cos(pi*90/90)-------> 112
the position is the point (0,112)------> is not the point S
<span>
case c) x(t)=-70 sin(pi*t/45) y(t)=56 cos(pi*t/45)
</span>x(t)=-70 sin(pi*90/45)------> 0
y(t)=56 cos(pi*90/45)
-------> 56
the position is the point (0,56)------> is equal to the point S----> is the solution
case d) x(t)=70 cos(pi*t/90) y(t)=-56 sin(pi*t/90)
x(t)=70 cos(pi*90/90)------> -70
y(t)=-56 sin(pi*90/90)-------> 0
the position is the point (-70,0)------> is not the point S
therefore
the answer is the option C
x(t)=-70 sin(pi*t/45) y(t)=56 cos(pi*t/45)
