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Alisiya [41]
2 years ago
11

Find the 96th term of the arithmetic sequence 1, -12, -25, ...

Mathematics
1 answer:
goldenfox [79]2 years ago
6 0

Answer:

The 96th term of the arithmetic sequence is -1234.

Step-by-step explanation:

first term (a)=1

second term (t2)=-12

common difference (d)= t2-a

d=-12-1

d=-13

96th term (t96)=?

We know that,

t96=a+(n-1)d

t96=1+(96-1)(-13)

t96=1+95(-13)

t96=1-1235

t96=-1234

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Pls help me
goldfiish [28.3K]

Answer:

area = 2604 in²

Step-by-step explanation:

area = L x W

area = 42 x 62 = 2604 in²

7 0
2 years ago
Select the term that does not describe the triangle. Select all that apply.
gulaghasi [49]

The answer is scalene

7 0
2 years ago
 The denominator of a fraction in simplest form is greater than the numerator by 3. If 7 is added to the numerator, and 5 added
jok3333 [9.3K]
So.. if we take the numerator to be say "a", then the denominator will be "a+3"

\bf \cfrac{a}{a+3}\textit{ if we add }\frac{1}{2}\textit{ we get then }\cfrac{a+7}{a+3+5}
\\\\\\
thus\implies \cfrac{a}{a+3}+\cfrac{1}{2}=\cfrac{a+7}{a+8}\\\\
-----------------------------\\\\
\cfrac{a+3+2a}{2(a+3)}=\cfrac{a+7}{a+8}\implies \cfrac{3a+3}{2a+6}=\cfrac{a+7}{a+8}
\\\\\\
3a^2+24a+3a+24=2a^2+14a+6a+42
\\\\\\
a^2+7a-18=0\implies (a+9)(a-2)=0
\\\\\\
a=
\begin{cases}
2\implies &\frac{2}{5}\\\\
-9\implies &\frac{3}{2}
\end{cases}

either of those two fractions will do
4 0
3 years ago
The probability of selecting an orange marble is 20%
zubka84 [21]

See there is no pink

So probability of selecting a pink is 0 .

The probability of orange is 20% or 0.2

The probability of purple is 30% or 0.3

As there is no color mentioned for rest part at max probability of pink is 0.5 .

  • But by now it's 0 as it's not mentioned
5 0
2 years ago
Evaluate. or Calculate the value
natta225 [31]

-- The difference of 2 logs is the log of the quotient of their arguments.

             log(11) - log(6) = log(11/6)

-- 1/3 of the log of something is the log of its cube root.
 
                     1/3 log(8) = log(∛8) = log(2)
and
                     1/3 log(729) = log(∛729) = log(9)

-- If a bunch of logs all have the same base, then their sum
is the log of the product of the arguments.  So ...

         log(11) - log(6) + 1/3 log(8) + 1/3 log(729)  =

         log(11/6 times 2 times 9)  =

         log( 11*18 / 6 )  =  <em>log(33)</em>

                                      log(33) = about <em>1.519</em> (rounded)

============================================

The other way:

log(11) =                  1.0414
-log(6) =                  -0.7782
log(8) = 0.9031
       1/3(0.9031) =     0.3010
log(729) = 2.8627
           1/3(2.8627) = 0.9542
                              -----------
Adum up:                 <em>1.5184</em>

(Note:  Everything is rounded.)


3 0
3 years ago
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