3 years ago

Find the 96th term of the arithmetic sequence 1, -12, -25, ...

Mathematics

1 answer:

goldenfox [79]3 years ago

6 0

Answer:

The 96th term of the arithmetic sequence is -1234.

Step-by-step explanation:

first term (a)=1

second term (t2)=-12

common difference (d)= t2-a

d=-12-1

d=-13

96th term (t96)=?

We know that,

t96=a+(n-1)d

t96=1+(96-1)(-13)

t96=1+95(-13)

t96=1-1235

t96=-1234

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