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WARRIOR [948]
3 years ago
15

Triangle PQR is formed by the three squares A, B, and C:

Mathematics
1 answer:
stiks02 [169]3 years ago
5 0

Answer:

hii there

your answer is here

(PQ)2 + (QR)2 = (PR)2, because 9 + 16 = 25

PQ + QR = PR, because 9 + 16 = 25

(PQ)2 + (QR)2 = (PR)2, because 52 + 32 = 42

PQ + QR = PR, because 52 + 32 = 42

Step-by-step explanation:

hope it helps

have a nice day : )

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PLEASE HELP ME ASAP ?!?!?
GaryK [48]

Answer:

m = 5 n = \frac{5\sqrt{3} }{2}

Step-by-step explanation:

5/2x2=5

5/3xsqrt3=5sqrt3/2

3 0
3 years ago
How to factor <br> 49y^{2}-9x^{2}
lorasvet [3.4K]

Answer:

(7y + 3x)(7y - 3x)

Step-by-step explanation:

a² - b² = (a + b)(a - b)

49y² - 9x² = (7y)² - (3x)²                   {a = 7y ; b - 3x}

               = (7y + 3x)(7y - 3x)

7 0
3 years ago
A study was conducted and two types of engines, A and B, were compared. Fifty experiments were performed using engine A and 75 u
USPshnik [31]

Answer:

a) -6 mpg.

b) 2.77 mpg

c) The 95% confidence interval for the difference of population mean gas mileages for engines A and B and interpret the results, in mpg, is (-8.77, -3.23).

Step-by-step explanation:

To solve this question, we need to understand the central limit theorem, and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Gas mileage A: Mean 36, standard deviation 6, sample of 50:

So

\mu_A = 36, s_A = \frac{6}{\sqrt{50}} = 0.8485

Gas mileage B: Mean 42, standard deviation 8, sample of 50:

So

\mu_B = 42, s_B = \frac{8}{\sqrt{50}} = 1.1314

Distribution of the difference:

Mean:

\mu = \mu_A - \mu_B = 36 - 42 = -6

Standard error:

s = \sqrt{s_A^2+s_B^2} = \sqrt{0.8485^2+1.1314^2} = 1.4142

A. Find the point estimate.

This is the difference of means, that is, -6 mpg.

B. Find the margin of error

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = zs = 1.96*1.4142 = 2.77

The margin of error is of 2.77 mpg

C. Construct the 95% confidence interval for the difference of population mean gas mileages for engines A and B and interpret the results(5 pts)

The lower end of the interval is the sample mean subtracted by M. So it is -6 - 2.77 = -8.77 mpg

The upper end of the interval is the sample mean added to M. So it is -6 + 2.77 = -3.23 mpg

The 95% confidence interval for the difference of population mean gas mileages for engines A and B and interpret the results, in mpg, is (-8.77, -3.23).

8 0
3 years ago
Amanda runs a consultancy firm. For a given year, her income from services was $30,700. Direct expenses incurred by her for the
defon
The answer is C 
30700-10500-500=19700 thats how much she walks away with. 
Also can i have brainliest answer if i am correct which i believe i am. 
8 0
3 years ago
Read 2 more answers
Pls help (9th honors geo - circles)
Mariana [72]

• Angles DXC and AXB form a vertical pair, so they are congruent and have the same measure.

• ∆ABD is isosceles, since it's given that AD and BD are congruent. This means the "base angles" BAD and ABD have the same measure; call this measure <em>x</em>.

• The measure of angle ADB can be computed by using the inscribed angle theorem, which says

m∠ADB = 1/2 (100°) = 50°

(that is, it's half the measure of the subtended arc AB whose measure is 100°)

• The interior angle to any triangle sum to 180° in measure. So we have in ∆ABD,

m∠ADB + 2<em>x</em> = 180°

Solve for <em>x</em> :

50° + 2<em>x</em> = 180°

2<em>x</em> = 130°

<em>x</em> = 65°

• Use the inscribed angle theorem again to find the measure of angle BAC. This will be half the measure of the subtended arc BC, so

m∠BAC = 1/2 (50°) = 25°

• Now in ∆ABX, we have

m∠AXB + 25° + 65° = 180°

m∠AXB = 90°

Hence m∠DXC = 90°.

6 0
3 years ago
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