Y-y1=a(x-x1)
a=(y2-y1)/(x2-x1)
a= (6-(-2))/(7-1)
a=8/6
a=4/3
y-6=4/3(x-7)
y-6=4/3x-28/3
y=4/3x-28/3+6
y=4/3x-10/3 >>ef
Alexis can wash a total of 14 windows in 1 hour
<h3><u>Solution:</u></h3>
Given that Alexis washes 
windows in 
hours
<u><em>To find: </em></u>number of windows washed in one hour
To simplify the calculations we will convert the given mixed fraction to improper fraction
Hence, to wash 10.5 windows, Alexis takes 0.75 hours
Let "n" be the number of windows washed in 1 hour
10.5 windows ⇒ 0.75 hours
"n" windows ⇒ 1 hour
By cross-multiplication we get,
Thus Alexis can wash 14 windows in one hour
Answer:
a) 5x=8 use a calculator and use distributive property
b) 22=3x+5 -18
22=3x-13
9=3x
x=3
distributive property
c)-48= -8x-20+5x-1
-48= -3x-21
-27= -3x
x=7
distributive property
Step-by-step explanation:
Answer: 6/12 are white, 3/12 are colored and 3/12 are albino.
Step-by-step explanation: If the horses are white and their parents are ccww (albino) and CCWw (white horse), according to Mendel's premises, they both must be CcWw, since the crossing provides one C from one parent and other c from the other parent, one W and the other w. Using Mendel's chess and the principle of independent segregation, the crossing between CcWw results in the following fenotypical ratio:
1/16 CCWW (lethal)
2/16 CCWw (white)
2/16 CcWW (lethal)
4/16 CcWw (white)
1/16 CCww (normal)
2/16 Ccww (normal)
2/16 ccWw (albino)
1/16 ccWW (lethal)
1/16 ccww (albino)
Excluding the 4 individuals that have the lethal locus, we have 6/12 that are white (2/12 + 4/12) and 3/12 (1/12 + 2/12) that are colored. Also, there are 3/12 of albino individuals as well.
69. Oh yes the memes indeed.
