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likoan [24]
3 years ago
7

1. The position of a particle moving along a coordinate axis is given by: s(t) = t^2 - 5t + 1. a) Find the speed of the particle

b) Find the acceleration of the particle c) Find the velocity of the particle
Mathematics
1 answer:
zimovet [89]3 years ago
3 0

Answer: \left |  2t-5\right |,\ 2,\ 2t-5

Step-by-step explanation:

Given

Position of the particle moving along the coordinate axis is given by

s(t)=t^2-5t+1

Speed of the particle is given by

\Rightarrow v=\dfrac{ds}{dt}\\\\\Rightarrow v=\dfrac{d(t^2-5t+1)}{dt}\\\\\Rightarrow v=\left |  2t-5\right |

Acceleration of the particle is

\Rightarrow a=\dfrac{dv}{dt}\\\\\Rightarrow a=2

velocity can be negative, but speed cannot

\Rightarrow v=\dfrac{ds}{dt}\\\\\Rightarrow v=\dfrac{d(t^2-5t+1)}{dt}\\\\\Rightarrow v=2t-5

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8. If BD=BC, BD = 5x -26, BC = 2r + 1, and AC = 43, find AB.
charle [14.2K]

Answer:

24

Step-by-step explanation:

BD=DC

5x-26=2x+1

5x-2x=1+26

3x=27

x=9

BC=2x+1

=2*9+1

BC =19

so AB=AC-BC

AB=43-19

AB=24

8 0
3 years ago
The following table shows the values of y for different values of x:
solmaris [256]

Answer:

Option B. It represents a nonlinear function because its points are not on a straight line.

Step-by-step explanation:

Let

A(0,0),B(1,1),C(2,4)

we know that

If point A,B and C are on a straight line

then

The slope of AB must be equal to the slope of AC

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

<em>Find the slope AB</em>

A(0,0),B(1,1)

substitute in the formula

m_A_B=\frac{1-0}{1-0}=1

<em>Find the slope AC</em>

A(0,0),C(2,4)

substitute in the formula

m_A_C=\frac{4-0}{2-0}=2

so

m_A_B\neq m_A_C

Points A, B and C are not on a straight line

therefore

It represents a nonlinear function because its points are not on a straight line

8 0
3 years ago
Read 2 more answers
3r+n^2-r+5-2n+2 simplify
andrey2020 [161]
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4 0
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3 0
4 years ago
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Vera_Pavlovna [14]
54÷x

Hope this helped................
5 0
3 years ago
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