Answer:
upper control limit = 6.058
lower control limit = 0.442
Step-by-step explanation:
Given that:
The numbers of sample n Mogul executives took = 8 Eagletrons at a time.
They find out that the average sample mean is 88.50 mph and;
the average range
is 3.25 mph.
From the tables:
![\text {Table values for n = 8 } \left \{ {{D_4=1.864} \atop {D_3=0.136}} \right.](https://tex.z-dn.net/?f=%5Ctext%20%7BTable%20values%20for%20n%20%3D%208%20%7D%20%5Cleft%20%5C%7B%20%7B%7BD_4%3D1.864%7D%20%5Catop%20%7BD_3%3D0.136%7D%7D%20%5Cright.)
Control Limit =
= 3.25
Therefore; the upper control limit and the lower control limit can be computed as follows:
upper control limit = ![D_4 \overline r](https://tex.z-dn.net/?f=D_4%20%5Coverline%20r)
upper control limit = 1.864(3.25)
upper control limit = 6.058
lower control limit = ![D_3 \overline r](https://tex.z-dn.net/?f=D_3%20%5Coverline%20r)
lower control limit = 0.136(3.25)
lower control limit = 0.442
The answer is going to be 124. hope that helped
Answer:
A) The amount of spread in the middle-half of Baltimore's data is greater than Seattle's
Step-by-step explanation:
![t=\frac{d}{v}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7Bd%7D%7Bv%7D)
t - time, d - distance, v - speed
Let x be Jaime's normal rowing speed.
The wind adds 2 miles per hour to her speed when she is rowing with the wind - so her speed is x+2, and she can row 60 miles at that speed in time t.
![t=\frac{60}{x+2}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B60%7D%7Bx%2B2%7D)
The wind subtracts 2 miles per hour from her speed when she is rowing against the wind - so her speed is x-2, and she can row 48 miles at that speed in the same time t.
![t=\frac{48}{x-2}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B48%7D%7Bx-2%7D)
Set the expressions for t equal to each other:
![\frac{60}{x+2}=\frac{48}{x-2} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{cross multiply} \\ 60(x-2)=48(x+2) \ \ \ \ |\div 12 \\ 5(x-2)=4(x+2) \\ 5x-10=4x+8 \\ 5x-4x=8+10 \\ x=18 ](https://tex.z-dn.net/?f=%5Cfrac%7B60%7D%7Bx%2B2%7D%3D%5Cfrac%7B48%7D%7Bx-2%7D%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%7C%5Chbox%7Bcross%20multiply%7D%20%5C%5C%0A60%28x-2%29%3D48%28x%2B2%29%20%5C%20%5C%20%5C%20%5C%20%7C%5Cdiv%2012%20%5C%5C%0A5%28x-2%29%3D4%28x%2B2%29%20%5C%5C%0A5x-10%3D4x%2B8%20%5C%5C%0A5x-4x%3D8%2B10%20%5C%5C%0Ax%3D18%0A)
Jaime's normal rowing speed is 18 miles per hour.