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My name is Ann [436]
3 years ago
15

What's the equation:

Mathematics
1 answer:
ElenaW [278]3 years ago
8 0

Using shifting concepts, it is found that the function g is:

g(x) = -9x^2 - 198x - 1085

-------------------------

  • The parent function is f(x) = x^2.

-------------------------

  • Horizontally stretching a function by a factor of b is the finding f(\frac{x}{b}).
  • Thus, horizontally stretching by a factor of 1/3, we have:

g(x) = f(\frac{x}{\frac{1}{3}}) = f(3x) = (3x)^2 = 9x^2

-------------------------

  • Reflecting vertically is finding -f(x)
  • Reflecting horizontally is finding f(-x).

Thus:

g(x) = -9(-x)^2 = -9x^2

-------------------------

  • Translating a units to the left is finding f(x + a), thus:
  • Translating 11 units to the left is finding f(x + 11), thus:

g(x) = -9(x + 11)^2 = -9(x^2 + 22x + 121) = -9x^2 - 198x - 1089

-------------------------

  • Shifting a units up is finding f(x) + a, thus:
  • 4 units up is finding f(x) + 4, thus:

g(x) = -9x^2 - 198x - 1089 + 4 = -9x^2 - 198x - 1085

A similar problem is given at brainly.com/question/23325498

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A quaderlateral has the following angle measurements :100,90,45, and?
Andrews [41]
The other angle would be 35
7 0
4 years ago
Find the absolute maximum and minimum values of f(x, y) = x+y+ p 1 − x 2 − y 2 on the quarter disc {(x, y) | x ≥ 0, y ≥ 0, x2 +
Andreas93 [3]

Answer:

absolute max: f(x,y)=1/2+p1 ; at P(1/2,1/2)

absolute min: f(x,y)=p1 ; at U(0,0), V(1,0) and W(0,1)

Step-by-step explanation:

In order to find the absolute max and min, we need to analyse the region inside the quarter disc and the region at the limit of the disc:

<u>Region inside the quarter disc:</u>

There could be Minimums and Maximums, if:

∇f(x,y)=(0,0) (gradient)

we develop:

(1-2x, 1-2y)=(0,0)

x=1/2

y=1/2

Critic point P(1/2,1/2) is inside the quarter disc.

f(P)=1/2+1/2+p1-1/4-1/4=1/2+p1

f(0,0)=p1

We see that:

f(P)>f(0,0), then P(1/2,1/2) is a maximum relative

<u>Region at the limit of the disc:</u>

We use the Method of Lagrange Multipliers, when we need to find a max o min from a f(x,y) subject to a constraint g(x,y); g(x,y)=K (constant). In our case the constraint are the curves of the quarter disc:

g1(x, y)=x^2+y^2=1

g2(x, y)=x=0

g3(x, y)=y=0

We can obtain the critical points (maximums and minimums) subject to the constraint by solving the system of equations:

∇f(x,y)=λ∇g(x,y) ; (gradient)

g(x,y)=K

<u>Analyse in g2:</u>

x=0;

1-2y=0;

y=1/2

Q(0,1/2) critical point

f(Q)=1/4+p1

We do the same reflexion as for P. Q is a maximum relative

<u>Analyse in g3:</u>

y=0;

1-2x=0;

x=1/2

R(1/2,0) critical point

f(R)=1/4+p1

We do the same reflexion as for P. R is a maximum relative

<u>Analyse in g1:</u>

(1-2x, 1-2y)=λ(2x,2y)

x^2+y^2=1

Developing:

x=1/(2λ+2)

y=1/(2λ+2)

x^2+y^2=1

So:

(1/(2λ+2))^2+(1/(2λ+2))^2=1

\lambda_{1}=\sqrt{1/2}*-1 =-0.29

\lambda_{2}=-\sqrt{1/2}*-1 =-1.71

\lambda_{2} give us (x,y) values negatives, outside the region, so we do not take it in account

For \lambda_{1}: S(x,y)=(0.70, 070)

and

f(S)=0.70+0.70+p1-0.70^2-0.70^2=0.42+p1

We do the same reflexion as for P. S is a maximum relative

<u>Points limits between g1, g2 y g3</u>

we need also to analyse the points limits between g1, g2 y g3, that means U(0,0), V(1,0), W(0,1)

f(U)=p1

f(V)=p1

f(W)=p1

We can see that this 3 points are minimums relatives.

<u>Conclusion:</u>

We compare all the critical points P,Q,R,S,T,U,V,W an their respective values f(x,y). We find that:

absolute max: f(x,y)=1/2+p1 ; at P(1/2,1/2)

absolute min: f(x,y)=p1 ; at U(0,0), V(1,0) and W(0,1)

4 0
3 years ago
Laura walks 1/2 mile every 10 minutes. At this rate how far will she walk in an hour?
gulaghasi [49]

well, an hour has 60 minutes, that means 10+10+10+10+10+10 minutes.

we know she can do ½ mile in 10 minutes, so in an hour, she'll be doing

½+½+½+½+½+½ miles, and you know how much that is.

8 0
3 years ago
Can anyone help me? SOOOOO hard!!
emmasim [6.3K]

Answer:

i think its 16/34

Step-by-step explanation:

8 0
3 years ago
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A certain brand of upright freezer is available in three different rated capacities: 16 ft3, 18 ft3, and 20 ft3. Let X = the rat
Mrac [35]

Answer:

E(X) = 17.4

Step-by-step explanation:

We can calculate the expected value of a random X variable that is discrete (X takes specific values ) as:

E(X) =  ∑xp(x)  where x are the specific values of x and p(x) the probability associated with this x value.

In this way the expexted value is

E(X) =  ∑xp(x) =(16*0.6)+(18*0.3)+(20*0.2) = 8+5.4+4 =  17.4

5 0
3 years ago
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