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2 years ago

10

Heather earns $16 for each hour she works as a lifeguard. Choose the equation that models the situation, where h represents the

number of hours she works and m represents the money she earns. m = 16 - h m = 16 h (0) m = 16h m = 16 + h ()

1 answer:

lord [1]2 years ago

5 0

Answer:

I'm pretty sure the answer is m = 16h

Hope this helps!

Please mark as brainliest!

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Mkey [24]

Answer:

1) 3,6,9

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Step-by-step explanation:

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Evaluate lim x approaches to 2 : (sqrt(6-x)-2)/(sqrt(3-x)-1)

solong [7]

Answer:

The answer is "0.5".

Step-by-step explanation:

Given:

$\to \lim_{x\to 2} \frac{(\sqrt{(6-x)}-2)}{(\sqrt{(3-x)}-1)}\\\\ \to \lim_{x\to 2} \frac{\frac{d(\sqrt{(6-x)}-2)}{dx}}{\frac{(\sqrt{(3-x)}-1)}{dx}}\\\\$

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$\to \lim_{x\to 2} \frac{\sqrt{3-x}}{\sqrt{6-x}}\\\\ \to \frac{\sqrt{3-2}}{\sqrt{6-2}}\\\\ \to \frac{\sqrt{1}} {\sqrt{4}}\\\\ \to \frac{1}{2}\\\\ \to 0.5$

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2 years ago

Which expression can be used to find 80% of 120?

Leya [2.2K]

Answer
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3 years ago

A radioactive substance decays at a continuous rate of 12% per year, and 90 mg of the substance is present in the year 2000. (a)

Alla [95]

Answer:

A(t) = 90e^0.12t ;

299 mg

Step-by-step explanation:

General Continous growth rate equation :

A = Pe^rt

A = amount present, t years after year of initial amount.

Here,

P = 90 mg, amount in year 2000

r = rate = 12% = 0.12

t = years after 2000

Therefore,

A is written as ;

A(t) = 90e^0.12t

Amount present in year 2010 ;

t = 2010 - 2000 = 10

A(10) = 90e^0.12(10)

A(10) = 90 * e^1.2

= 90 * 3.3201169

= 298.81052

= 299 mg

5 0

2 years ago