Log3(7) + log3(x)
Terms that are multiplied inside one log become added when you separate them where each term gets its own log.
Answer:
C) Izzy
Step-by-step explanation:
Justin typed 90 words in 2 minute:
work
405/9=45 words a minute
45*2=90
Remmy typed 84 words in 2 minute:
work
420/10=42 words a minute
42*2=84
Izzy typed 98 words in 2 minutes:
work
588/12= 49 words a minute
49*2 = 98
I hope this helps :)
Answer:
D.
Bob should use the mean to make his selling price look like it's the greatest.
Answer:
there are 9 quarters and 19 dimes
Step-by-step explanation:
Let x be the number of dimes and y the number of quarters
-dimes: 0.1x
-quarters: 0.25y
-the total amount of coins : x + y = 28
=> x = 28 - y
We have the equation:
0.25y + 0.1x = 4.15
0.25y + 0.1(28 - y) = 4.15
0.25y + 2.8 - 0.1y = 4.15
0.15y = 1.35
y = 9
x = 28 - y
= 28 - 9
= 19
Let the three gp be a, ar and ar^2
a + ar + ar^2 = 21 => a(1 + r + r^2) = 21 . . . (1)
a^2 + a^2r^2 + a^2r^4 = 189 => a^2(1 + r^2 + r^4) = 189 . . . (2)
squaring (1) gives
a^2(1 + r + r^2)^2 = 441 . . . (3)
(3) ÷ (2) => (1 + r + r^2)^2 / (1 + r^2 + r^4) = 441/189 = 7/3
3(1 + r + r^2)^2 = 7(1 + r^2 + r^4)
3(r^4 + 2r^3 + 3r^2 + 2r + 1) = 7(1 + r^2 + r^4)
3r^4 + 6r^3 + 9r^2 + 6r + 3 = 7 + 7r^2 + 7r^4
4r^4 - 6r^3 - 2r^2 - 6r + 4 = 0
r = 1/2 or r = 2
From (1), a = 21/(1 + r + r^2)
When r = 2:
a = 21/(1 + 2 + 4) = 21/7 = 3
Therefore, the numbers are 3, 6 and 12.
