Answer:
2.9375% Rounded or 2.94% not rounded
Step-by-step explanation:
Answer:
Here we will use algebra to find three consecutive integers whose sum is 300. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 300. Therefore, you can write the equation as follows:
(X) + (X + 1) + (X + 2) = 300
To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:
X + X + 1 + X + 2 = 300
3X + 3 = 300
3X + 3 - 3 = 300 - 3
3X = 297
3X/3 = 297/3
X = 99
Which means that the first number is 99, the second number is 99 + 1 and the third number is 99 + 2. Therefore, three consecutive integers that add up to 300 are 99, 100, and 101.
99 + 100 + 101 = 300
We know our answer is correct because 99 + 100 + 101 equals 300 as displayed above.
Step-by-step explanation:
For this question, the equation I got was (x+3)^2 + (y-6)^2 = r^2.
Answer:
x = 4y + 5
Step-by-step explanation:
x represents the total students in the class. We don't know how many teams of four there will be, so we represent that with y. 4y represents the total students in teams of 4. We know there is one team of 5, so that is added to 4y.
Answer: x = 995
Step-by-step explanation:
In this equation our log doesn't have a base so it is given the default base of 10. This makes our equation really.
Now we put every equation as the exponent of our base 10 looks like this:
Now we cancel out the log base 10 and the 10. We are left with:
(x+3) + (2) = 10^3
Lastly solve for x
x + 5 = 1000
x = 995
