Question

Ok this is getting annoying but I gotta do this so I can pass

Answer 1

Answer:

$\sqrt{25} < \sqrt{29} < \sqrt{36}$

Answer 2

Answer:

5 < √(29) < 6

Step-by-step explanation:

1. First, we have to square the square root of 29.

• $\sqrt{29^2}$
• $29$

2. Alright, so now we know that the two digits when squared have 29 between them. Now, we have to find the digits.

3. When 5 is squared, we get 25. When 6 is squared, we get 36. This means that 29 is between 25 and 36, and we can write it as this statement: $25 < 29 < 36$.

4. Since the question is asking which two integers complete the statement, we just have to square root all the numbers.

• $\sqrt{25} < \sqrt{29} < \sqrt{36}$
• $5 < \sqrt{29} < 6$

Therefore, the answer is 5 < √(29) < 6.