Question

HELP ME SOMEONE PLSSSSSSSS ANSWER THE QUESTIONS. AND PLSS PLS EXPLAIN. ANSWER ALL OF THEM.

Answer 1

Answer: Check out the attached diagram below for the filled out table.

Explanation:

• A) This is correct. You basically stick a minus sign out front to reflect over the x axis (aka the line y = 0).
• B) Replacing x with x+2 will shift the graph 2 units to the left. Adding on 3 at the end will shift it up 3 units.
• C) A vertical stretch, aka vertical dilation, makes the graph taller than it already is. In this case, we want to stretch it to make it twice as tall. That explains the 2 out front. The negative is there to reflect over the x axis.
• D) The -2 is to apply a dilation of 2 and do a reflection. The +6 is so ensure that the vertex arrives at the proper location (0,6) so that we reflect over y = 3.
• E) This is similar to part B. Replacing x with x-3 shifts the graph 3 units to the right. We subtract off 2 at the end to shift the graph down 2 units. The 1/2 out front applies the dilation, which in this case is a vertical compression by a factor of 2.
• F) A vertical compression by a factor of 4 is the same as dilating by a factor of 1/4. So we'll multiply f(x) by 1/4.
• G) Similar to part F, but we'll be using the scale factor 4 this time.

Answer 2

Answer:

b. $f(x + 2) - 3$   and  $f(x) = |x+2| -3$

c. $2 f(-x)$  and  $f(x) = 2|-x|$

d. $2f(x) + 2|f(x) - 3|$  and  $f(x) = 2|x| + 2||x|-3|$

e. $\frac{f(x-2)}{2}+ 3$  and $f(x) = \frac{|x-2|}{2} + 3$

f. $\frac{f(x)}{4}$  and $f(x) = \frac{|x|}{4}$

g. $4f(x)$  and $f(x) = 4|x|$

Step-by-step explanation:

I'm not 100% on d and e, but I hope this helps