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2 years ago

1) A shirt went from $8 to $10.

Mathematics

1 answer:

bagirrra123 [75]2 years ago

7 0

Answer:

1) 20% change I think its an increase.

If needed I could try to answer the 2nd question but I am sure that I got the first one right.

Step-by-step explanation:

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Will mark brainliest! The triangles shown below must be congruent, true or false

olchik [2.2K]

True because they have the same size angles

8 0

2 years ago

Read 2 more answers

Sam wants to write an equation to represent a proportional relationship with a constant of proportionality of 6 he write y = 6 +

Olin [163]

Answer:

y = 6x

Step-by-step explanation:

The equation representing a proportional relationship is

y = kx ← k is the constant pf proportionality

Here k = 6 , then

y = 6x ← equation of proportion

7 0

3 years ago

Draw a picture of the standard normal curve and shade the area that corresponds to the requested probabilities. Then use the sta

elena-14-01-66 [18.8K]

Answer:

a)P [ z > 1,38 ] = 0,08379

b) P [ 1,233 < z < 2,43 ] = 0,1012

c) P [ z > -2,43 ] = 0,99245

Step-by-step explanation:

a) P [ z > 1,38 ] = 1 - P [ z < 1,38 ]

From z-table P [ z < 1,38 ] = 0,91621

P [ z > 1,38 ] = 1 - 0,91621

P [ z > 1,38 ] = 0,08379

b) P [ 1,233 - 2,43 ] must be P [ 1,233 < z < 2,43 ]

P [ 1,233 < z < 2,43 ] = P [ z < 2,43 ] - P [ z > 1,233 ]

P [ z < 2,43 ] = 0,99245

P [ z > 1,233 ] = 0,89125 ( approximated value without interpolation)

Then

P [ 1,233 < z < 2,43 ] = 0,99245 - 0,89125

P [ 1,233 < z < 2,43 ] = 0,1012

c) P [ z > -2,43 ]

Fom z-table

P [ z > -2,43 ] = 1 - P [ z < -2,43 ]

P [ z > -2,43 ] = 1 - 0,00755

P [ z > -2,43 ] = 0,99245

8 0

2 years ago

Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩

NISA [10]

Answer:

$\theta = 108.29$

Step-by-step explanation:

Given

$u =$

$v =$

Required:

Calculate the angle between u and v

The angle $\theta$ is calculated as thus:

$cos\theta = \frac{u.v}{|u|.|v|}$

For a vector

$A =$

$A = a * b$

$cos\theta = \frac{u.v}{|u|.|v|}$ becomes

$cos\theta = \frac{.}{|u|.|v|}$

$cos\theta = \frac{2*6+4*-7}{|u|.|v|}$

$cos\theta = \frac{12-28}{|u|.|v|}$

$cos\theta = \frac{-16}{|u|.|v|}$

For a vector

$A =$

$|A| = \sqrt{a^2 + b^2}$

So;

$|u| = \sqrt{2^2 + 6^2}$

$|u| = \sqrt{4 + 36}$

$|u| = \sqrt{40}$

$|v| = \sqrt{4^2+(-7)^2}$

$|v| = \sqrt{16+49}$

$|v| = \sqrt{65}$

So:

$cos\theta = \frac{-16}{|u|.|v|}$

$cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}$

$cos\theta = \frac{-16}{\sqrt{2600}}$

$cos\theta = \frac{-16}{\sqrt{100*26}}$

$cos\theta = \frac{-16}{10\sqrt{26}}$

$cos\theta = \frac{-8}{5\sqrt{26}}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})$

$\theta = cos^{-1}(\frac{-8}{5 * 5.0990})$

$\theta = cos^{-1}(\frac{-8}{25.495})$

$\theta = cos^{-1}(-0.31378701706)$

$\theta = 108.288386087$

<em></em> $\theta = 108.29$ <em> (approximated)</em>

4 0

2 years ago

Find the equation of the line. use exact numbers.

svp [43]

Answer:

y=4x -9

Step-by-step explanation:

y intercept- where the line crosses the y-axis (-9)

Rise over run- 4

6 0

3 years ago