Answer:
If I am assuming sqrt(200), the answer is C
Step-by-step explanation:
Because 200 is between both of these numbers, c is the only viable option
<span>326/1000 or 32.6% because .326 is in the thousandths place, you know it must be 326 out of 1000. also, 326 is 32.6% of 1000</span>
Answer: the range for one game is {$0, $2,590,000}
Step-by-step explanation:
The revenue, on average, can be written as:
Y = $35*x
where y is the revenue and x is the number of tickets sold.
The domain of this function is equal to {0, 74000} this means that they can sell any whole number of tickets between 0 and 74000.
To find the range we need to evaluate y in bot extremes of the domain (because we have a linear relation)
minimum revenue
y(0) = $35*0 = $0
maximum revenue
y(74000) = $35*74000 = $2,590,000
So the range for one game is {$0, $2,590,000}
<span>
s(33) = 33*50 = 1650 (amphetheater capacity) </span>
