Answer:
a) 2x+3
b) 5x-7
c) 2x-10
d) 3x/2
Step-by-step explanation:
the number considered is x
Answer:

Step-by-step explanation:
GIVEN: A farmer has
of fencing to construct a rectangular pen up against the straight side of a barn, using the barn for one side of the pen. The length of the barn is
.
TO FIND: Determine the dimensions of the rectangle of maximum area that can be enclosed under these conditions.
SOLUTION:
Let the length of rectangle be
and
perimeter of rectangular pen 


area of rectangular pen 

putting value of 


to maximize 



but the dimensions must be lesser or equal to than that of barn.
therefore maximum length rectangular pen 
width of rectangular pen 
Maximum area of rectangular pen 
Hence maximum area of rectangular pen is
and dimensions are 
Answer: 65200
7 - 1 = 6 x 11700 = 70200 - 5000 = 65200
Answer:
9
Step-by-step explanation:
divied by 3
27 divided by 3 is 9
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Answer:
15 ft
Step-by-step explanation:
Hi, the illustration for the problem is a right triangle with:
hypotenuse (C)= the length of the ladder = L
horizontal side(A) = distance from bottom of the ladder to the building = L - 6
vertical side(B) = distance from the top of the ladder to the bottom of the building = L - 3
So, we can use Pythagoras formula:
A2 +B2= C2
(L – 6 )² + (L-3)² = L²
L²-12L+36+L²-6L+9 =L²
L2 -18L+45 =0
APPLYING QUADRATIC FORMULA WE OBTAIN:
L =15 OR L=3
If L=3
Vertical side = L-3 = 0 (Length can´t be 0)
So L=15