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3 years ago

6

1. A bookstore owner wishes to generate

1 answer:

iVinArrow [24]3 years ago

8 0

12

add them you can even get together with someone and do each one

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Find the smallest value of $x$ such that $x^2 + 10x + 25 = 8$. <img src="https://tex.z-dn.net/?f=Find%20the%20smallest%20value%2

svetoff [14.1K]

Answer:

$x =-5\ - \sqrt{8}$

Step-by-step explanation:

Given

$x^2 + 10x + 25 = 8$

Required

Find the smallest value of x

$x^2 + 10x + 25 = 8$

Expand the expression on the right hand side

$x^2 + 5x + 5x + 25 = 8$

Factorize

$x(x+5)+5(x+5) = 8$

$(x+5)(x+5) = 8$

$(x+5)^2 = 8$

Take Square root of both sides

$\sqrt{(x+5)^2} = \±\sqrt{8}$

$(x+5) = \±\sqrt{8}$

Remove bracket

$x+5 = \±\sqrt{8}$

Subtract 5 from both sides

$x+5-5 =-5\± \sqrt{8}$

$x =-5\± \sqrt{8}$

$x =-5\ + \sqrt{8}$ or $x =-5\ - \sqrt{8}$

Comparing both values of x;

The smallest value of x is

$x =-5\ - \sqrt{8}$

4 0

3 years ago