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Mandarinka [93]
3 years ago
15

Y + x = 11 solve for y

Mathematics
1 answer:
Alecsey [184]3 years ago
4 0

<em>Y can equal 5 or 6 and many different numbers.</em>

<em>Same with x.</em>

  • <em>6+x=11</em>
  • <em>5+x=11</em>

<em>Lets fill in x and y in both.</em>

  • <em>6+5=11</em>
  • <em>5+6=11.</em>
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Simplify the given expression below: (4+2i)-(1–7i)
emmasim [6.3K]

Answer:

3 + 9i

Step-by-step explanation:

(4 + 2i) - (1 - 7i)

distribute the (-)

(4 + 2i) - 1 + 7i

combine like terms

3 + 9i

4 0
3 years ago
A population of rabbits on a farm grows by 12% each year. Assume that this increase occurs as new baby rabbits at the beginning
jolli1 [7]

Answer:

a) r₁₂ = 104.36

In general, rₙ = arⁿ⁻¹

b)

- rabbit food consumed during the 10th year is approximately 832 pounds

- rabbit food consumed in total for the 1st through 10th years is approximately 5265 pounds

Step-by-step explanation:

Given that:

r1 = 30 and a farm grows by 12%

a = 30 and the common ratio r = 1.12

now

n           r

1        30.00

2       33.60

3       37.63

4       42.15

5       47.21

6       52.87

7       59.21

8       66.32

9       74.28

10      83.19

11       93.18

12      104.36

Therefore r₁₂ = 104.36

In general, rₙ = arⁿ⁻¹

b)

if each rabbit consume 10 lbs of rabbit food each year

n           r                food consumed(lbs)

1        30.00               300

2       33.60               336

3       37.63                376

4       42.15                422

5       47.21                472

6       52.87               529

7       59.21                592

8       66.32               663

9       74.28               743

10      83.19                832

total                          5265

Therefore, the rabbit food consumed during the 10th year is approximately 832 pounds

And the rabbit food consumed in total for the 1st through 10th years is approximately 5265 pounds

6 0
2 years ago
Factor *<br> (x^2/9)- 64
Hoochie [10]

Step-by-step explanation:

We use

a ^{2}  -  \times ^{2}  = (a -  \times )(a +  \times )

Now we have

\frac{ { \times }^{2} }{9}  - 64 = ( \frac{ \times }{3} ) ^{2}  -  {8}^{2}  \\  = ( \frac{ \times }{3}  - 8)( \frac{ \times }{3}  + 8)

Hope that useful for you

5 0
3 years ago
What is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)?
Rasek [7]

The side lengths of triangle are 6 units, 8 units and 10 units.

<u>SOLUTION: </u>

Given that, we have to find what is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)  

We know that, distance between two points P\left(x_{1}, y_{1}\right) \text { and } Q\left(x_{2}, y_{2}\right) is given by  

P Q=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}

Now,  

\begin{array}{l}{\text { Distance between }(-5,-1) \text { and }(-5,5)=\sqrt{(-5-(-5))^{2}+(5-(-1))^{2}}} \\\\ {\qquad \begin{array}{l}{=\sqrt{(-5-(-5))^{2}+(5-(-1))^{2}}} \\\\ {=\sqrt{(0)^{2}+(5+1)^{2}}=\sqrt{(6)^{2}}=6} \\\\ {=\sqrt{(-5)^{2}+(5+1)^{2}+(5-(-1))^{2}}} \\\\ {=\sqrt{(-8)^{2}+(5+1)^{2}}=\sqrt{64+36}=\sqrt{100}=10} \\\\ {=\sqrt{(3-1)^{2}+(-1-(-1))^{2}}} \\\\ {=\sqrt{(5+3)^{2}+(0)^{2}}=\sqrt{(8)^{2}}=8}\end{array}}\end{array}

8 0
3 years ago
Cindy's age, x, is 3 times her age 6 years ago which equation represents the statement x=3(x-6) or x=3-6x or x=3x-6 or x=3x+6
WINSTONCH [101]
Let's denote Cindy's age which is unknown with X
We know that Cindy's age is 3 times her age 6 years ago. 
6 years ago Cindy's age was the present age (X) - 6 : X-6
The fact that the  present age is 3 times her age 6 year ago can be written as:
3*(X-6)
So, finally:
X=3*(X-6)
8 0
3 years ago
Read 2 more answers
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