Answer:
Step-by-step explanation:
7 x 8 = 56 (5 *x) +16
56=5x+16
-16 -16
40=5x
/5 /5
8 =x
Answer:6x+25
109
Step-by-step explanation:
X is the amount of years since 1995
2009 is 14 years so plug in 14 for x and solve
Step-by-step explanation:
Dividing my dog's age (X) by 4 and adding 6
is the same (=) as dividing my dog's age (x) by 8 and adding 8. ![\frac{x}{8} +8](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B8%7D%20%2B8)
![\frac{x}{4}+6=\frac{x}{8}+8](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B4%7D%2B6%3D%5Cfrac%7Bx%7D%7B8%7D%2B8)
4d = 24 would be the right equation. To double check you would divide both sides by 4 (the number of legs) to find the amount of dogs.
<em>p</em> … <em>q</em> … ¬<em>q</em> … <em>p</em> ∨ ¬<em>q</em> … (<em>p</em> ∨ ¬<em>q</em>) ⇒ <em>q</em>
T … T … F … T … T
T … F … T … T … F
F … T … F … F … T
F … F … T … T … F
Start with the first two columns, taking every possible pair of True/False for <em>p</em> and <em>q</em>.
¬<em>q</em> is just the negation of <em>q</em>, so True becomes False and False becomes True.
<em>p</em> ∨ <em>q</em> is the logical disjunction, or logical "or". It's True if either <em>p</em> or <em>q</em> is True, and False otherwise. So <em>p</em> ∨ ¬<em>q</em> is True only if either <em>p</em> or ¬<em>q</em> is True.
<em>p</em> ⇒ <em>q</em> is the logical implication. It's True only when both <em>p</em> and <em>q</em> are True, or when <em>p</em> is False. So (<em>p</em> ∨ ¬<em>q</em>) ⇒ <em>q</em> is True when both <em>p</em> ∨ ¬<em>q</em> and <em>q</em> are True, or when <em>p</em> ∨ ¬<em>q</em> is False.