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3 years ago

What is the doubling time?

2 answers:

7 0

The doubling time is the period of time required for a quantity to double in size or value. It is applied to population growth, inflation, resource extraction, consumption of goods, compound interest, the volume of malignant tumours, and many other things that tend to grow over time.

belka [17]3 years ago

5 0

Doubling time is the amount of time it takes for a given quantity to double in size or value at a constant growth rate. We can find the doubling time for a population undergoing exponential growth by using the Rule of 70. To do this, we divide 70 by the growth rate (r).

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Please help me also explain your answer so I can get better at this thank you :)

Elina [12.6K]

Answer: 880

Explanation: 132/0.15 = 880 sry it wasnt thorough explanation i dont have time

6 0

2 years ago

Read 2 more answers

Are two equilateral triangles always similar

sukhopar [10]

Yes because all equilateral triangles have equal angles and side lengths so they are all similar. hope i helped -J

4 0

3 years ago

Write an equation in standard form of the line that contains the point (-1,2) amd is perpendicular to y = 3x - 1

Strike441 [17]

Since it is perpendicular to y=3x-1, the slope must be a negative reciprocal.
there the slope of the perpendicular line is $-\frac{1}{3} x$

So now we have,
$y=- \frac{1}{3} x+b$

To find b, we use the point that the line passes through and substitute it to the y and x values.

$2=- \frac{1}{3} (-1)+b$

which would give us b=5/3

Therefore, the equation of the line is
$y=- \frac{1}{3} x+ \frac{5}{3}$

7 0

3 years ago

Data is collected to compare two different types of batteries. We measure the time to failure of 12 batteries of each type. Batt

-Dominant- [34]

Using the t-distribution, it is found that since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

At the null hypothesis, it is tested if it does not outlast by more than 2 hours, that is, the subtraction is not more than 2:

$H_0: \mu_B - mu_A \leq 2$

At the alternative hypothesis, it is tested if it outlasts by more than 2 hours, that is:

$H_1: \mu_B - \mu_A > 2$

The sample means are: $\mu_A = 8.65, \mu_B = 11.23$

The standard deviations for the samples are $s_A = s_B = 0.67$

Hence, the standard errors are:

$s_{Ea} = S_{Eb} = \frac{0.67}{\sqrt{12}} = 0.1934$

The distribution of the difference has mean and standard deviation given by:

$\overline{x} = \mu_B - \mu_A = 11.23 - 8.65 = 2.58$

$s = \sqrt{s_{Ea}^2 + s_{Eb}^2} = \sqrt{0.1934^2 + 0.1934^2} = 0.2735$

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{s}$

In which $\mu = 2$ is the value tested at the hypothesis.

Hence:

$t = \frac{\overline{x} - \mu}{s}$

$t = \frac{2.58 - 2}{0.2735}$

$t = 2.12$

The critical value for a right-tailed test, as we are testing if the subtraction is greater than a value, with a 0.05 significance level and 12 + 12 - 2 = 22 df is given by $t^{\ast} = 1.71$

Since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

A similar problem is given at brainly.com/question/13873630

7 0

2 years ago

While catching fi refl ies, you and a friend decide to have a competition. After m minutes, you have (3m + 13) fi refl ies and y

Lostsunrise [7]

A. (3m + 13) + (4m + 6)

B. you: (3*5 + 13) = 28

friend: (4*5 + 6) = 26

You have more fireflies

3 0

3 years ago