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erma4kov [3.2K]
2 years ago
8

125.7-1.82 plzz include steps

Mathematics
1 answer:
Talja [164]2 years ago
4 0
You just subtract it 125 - 1.82 and it gives you 123.88. i dont know how else to explain
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What's the prime factorization of 105
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105 is a composite number. 105 = 1 x 105, 3 x 35, 5 x 21, 7 x 15. Factors of 105: 1, 3, 5, 7, 15, 21, 35, 105. Prime factorization: 105 = 3 x 5 x 7.
8 0
3 years ago
If a carton contains 6 eggs, how many eggs are there in 13 cartons? would it be 6x13?? which is equal to 78 I'm not sure.
qwelly [4]

Answer:

<em>78 eggs</em>

Step-by-step explanation:

13 × 6 = 78 eggs

Hope this helps! :)

6 0
3 years ago
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Conjecture about the properties that change and the
Makovka662 [10]

Answer:

A and C on Edge

Step-by-step explanation:

Just completed the assignment

7 0
3 years ago
The Johnson family pays $19.75 at the game for 3 ice cream cones and 4 funnel cakes. The Duke family pays $35.25 at the same gam
postnew [5]

Answer:

$1.75  cost of the funnel cake and $4.25 cost of the ice cream cone.

Step-by-step explanation:

x = cost of the ice cone cone

y = cost of the funnel cake

3x + 4y = 19.75      multiply (-2)       ⇔     -6x - 8y = -39.50

5x + 8y = 35.25    do not change   ⇔  +<u>  5x + 8y = 35.25</u>

                                                                     -x  =  -4.25

                                                                      x = 4.25  cost of the ice cream cone

Substitute into the second equation x = 4.25 and solve  for y

5(4.25) + 8y = 35.25

21.25 + 8y = 35.25

  8y = 14

y = 1.75    cost of the funnel cake

7 0
2 years ago
The mean incubation time of fertilized eggs is 19 days. Suppose the incubation times are approximately normally distributed with
kotykmax [81]

Answer:

Step-by-step explanation:

Since the incubation times are approximately normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = incubation times of fertilized eggs in days

µ = mean incubation time

σ = standard deviation

From the information given,

µ = 19 days

σ = 1 day

a) For the 20th percentile for incubation times, it means that 20% of the incubation times are below or even equal to 19 days(on the left side). We would determine the z score corresponding to 20%(20/100 = 0.2)

Looking at the normal distribution table, the z score corresponding to the probability value is - 0.84

Therefore,

- 0.84 = (x - 19)/1

x = - 0.84 + 19 = 18.16

b) for the incubation times that make up the middle 97​% of fertilized eggs, the probability is 97% that the incubation times lie below and above 19 days. Thus, we would determine 2 z values. From the normal distribution table, the two z values corresponding to 0.97 are

1.89 and - 1.89

For z = 1.89,

1.89 = (x - 19)/1

x = 1.89 + 19 = 20.89 days

For z = - 1.89,

- 1.89 = (x - 19)/1

x = - 1.89 + 19 = 17.11 days

the incubation times that make up the middle 97​% of fertilized eggs are

17.11 days and 20.89 days

6 0
3 years ago
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