21 x 9 = 9 x 21 is the commutative property.
First, Divide by 3 on both sides.
So 3x=12 will turn to 3x/3=12/3
Which isolates the variable x and the answer: x= 4
(1) circumference of a circle = 2π.R
(2) area of a circle = π.R²
Area = 452.16 m² (given), so we can calculate the radius:
452.16 = π.R²
452.16/π = R²
143.92 = R² → R =√143.92 ≈ 12 m
Having R = 12, now we can calculate the circumference :
circumference of a circle = 2π.R = 2.π.12 = 75.41 m
The legnth is irrelivant
we know that
Circumference=2 times pi time radius
c=40
40=2 times pi times radius
divide both sides by 2
20=pi times radius
divide both sides b pi
20/pi=radius
the radius is 20/pi cm or aproximately 6.366199048 cm
Answer:
The width is ![24.5in](https://tex.z-dn.net/?f=24.5in)
Step-by-step explanation:
The perimeter of the rectangular yoga mat can be found using the formula;
.
.
It was given that the width of the mat is eight less than half the length.
![w=\frac{1}{2}l-8...(2)](https://tex.z-dn.net/?f=w%3D%5Cfrac%7B1%7D%7B2%7Dl-8...%282%29)
We put equation (2) into equation (1) to get;
.
.
.
![\Rightarrow 3l=195](https://tex.z-dn.net/?f=%5CRightarrow%203l%3D195)
Divide both sides by 3;
![l=65](https://tex.z-dn.net/?f=l%3D65)
We put
into equation 2 to get;
![w=\frac{1}{2}\times65-8](https://tex.z-dn.net/?f=w%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes65-8)
![w=32.5-8](https://tex.z-dn.net/?f=w%3D32.5-8)
![w=24.5in](https://tex.z-dn.net/?f=w%3D24.5in)