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xenn [34]
3 years ago
11

The weights, in pounds, of the upper-class men offensive line players for a college are shown below: 322, 290, 321, 326, 330, 31

5, 311, 292, 290 What is the average, or mean, weight of the upper-class men offensive players? Provide your answer with 3 sig figs. -311 pounds -315 pounds -290 pounds -318 pounds
Mathematics
2 answers:
I am Lyosha [343]3 years ago
8 0

Answer: 311 pounds

Step-by-step explanation:

To find the average, add up all of the values and divide by the amount of values.

First add up all of the values.

322+290+321+326+330+315+311+292+290 = 2797

Now count how many values there are and divide your previous sum by it.

2797/9 = 310.78

Because you need to have 3 sig figs, round to the nearest one.

310.78 rounds up to 311.

amm18123 years ago
8 0

answer-311

Step-by-step explanation:

322+290+321+326+330+315+311+292+290=2797

Count the number of values and divide by 2797

2797 divided by 9 =310.77777777777777

Nearest one-311

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20≥8+4.99x please I could get an F.
marin [14]

Answer:

\begin{bmatrix}\mathrm{Solution:}\:&\:x\le \frac{1200}{499}\:\\ \:\mathrm{Decimal:}&\:x\le \:2.40480\dots \\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:\frac{1200}{499}]\end{bmatrix}

Step-by-step explanation:

20\ge \:8+4.99x\\Switch\:sides\\8+4.99x\le \:20\\\mathrm{Multiply\:both\:sides\:by\:}100\\8\cdot \:100+4.99x\cdot \:100\le \:20\cdot \:100\\Refine\\800+499x\le \:2000\\\mathrm{Subtract\:}800\mathrm{\:from\:both\:sides}\\800+499x-800\le \:2000-800\\Simplify\\499x\le \:1200\\\mathrm{Divide\:both\:sides\:by\:}499\\\frac{499x}{499}\le \frac{1200}{499}\\Simplify\geq \\x\le \frac{1200}{499}

5 0
3 years ago
The number of Calories c that are burned by walking depends on t, the number of hours spent walking. If you burn 300 Cal/h, how
Paladinen [302]

300/2.5= 120 Calories

4 0
3 years ago
An ancient Sicilian legend says that the barber in a remote town who can be reached only by traveling a dangerous mountain road
faust18 [17]

Answer:

No there cannot be.

Step-by-step explanation:

In explaining this question, I would like us to take into account who the barber is,

" the barber is the one who shaves all those, and those only, who do not shave themselves".

This barber cannot be in existence because who would shave him? If he should shave himself then there is a violation of the rule which says he shaves only those who do not shave themselves. If he shaves himself then he ceases to be a barber. And if he does not shave himself then he happens to be under those who must be shaved by the barber, because of what the rule says. But then he is the barber.

This lead us to a contradiction.

Neither is possible so there is no such barber.

4 0
4 years ago
Kara and Steven are biking around a 1,800 kilometer path. They start biking from the same place, at the same time, and in the sa
levacccp [35]
It would take them 120 hours to get to the same point on the path again.

Kara is traveling at half the speed of Steven. Therefore, we Steven finishes his second lap Kara will just be finishing her first lap. They will both be at the starting lap again.

It will take Kara 120 hours to complete the lap. 
1800 / 15 = 120  

(That is a lot of time, do you have the numbers correct?)
3 0
3 years ago
Solve for xx. Round to the nearest tenth, if necessary.
jasenka [17]

Step-by-step explanation:

S+T+U=180°{sum of angle of triangle}

  • 68°+90°+U=180°
  • U=180-158°
  • U=22°

sin theta= p/h

sin22°=x/83

o.37=x/83

x=0.37×83

x=30.71

x=31

stay safe healthy and happy.

6 0
3 years ago
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