Answer:
10
Step-by-step explanation:
First, multiply everything in the parentheses.
Next, subtract 21x from both sides to get all the variables on one side.
Next, add 16 to both sides to get all the real numbers on one side
Finally, divide both sides by 30 so we can get the variable by it's self
There are eight different possibilities for outcomes of three tosses:
<span>1. Head, Head, Head
2. Head, Head, Tail
3. Head, Tail, Head
4. Head, Tail, Tail
5. Tail, Head, Head
6. Tail, Head, Tail
7. Tail, Tail, Head
8. Tail, Tail, Tail</span>
The 8th possibility will not give us at least 1 head so we will cross that one out. So there is a 1/7 possibility for at least 1 head.
What do you mean by that:(
Okay i get it now
1) At 1.30 p.m. the barge has already traveled 4.5 X 10 = 45 miles.
To catch up it will take the train 25-10 = 15miles
Let the two numbers be x and y
x/y=3/4
Therefore x=3z
y=4z, where z is the GCF of x and y
(3z+k)/(4z+k)=4/5
(3z+k)*5=(4z+k)*4
15z+5k=16z+4k
k=z--->eq1
3z+k+4z+k=117
7z+2k=117--->eq2
Using value of z from eq1 in eq2
7k+2k=117
k=117/9
=13