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Paul [167]
3 years ago
11

Hi I need help, I need someone to explain this. I'll mark brainliest.

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
8 0

Answer:

The supplement is 98°

Step-by-step explanation:

To find the supplement of an angle, subtract it from 180. so 180-82=98

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from a window 24 feet above the ground, the angle of elevation to the top of another building is 38 degrees. The distance betwee
Delvig [45]

Answer:

The  height of the building is 73.2\ ft

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

In the right triangle ABC

tan(38\°)=\frac{BC}{AB}

we have

AB=63\ ft

substitute and solve for BC

tan(38\°)=\frac{BC}{63}

BC=(63)tan(38\°)=49.2\ ft

Find the height of the building

The  height of the building (h) is equal to

h=BC+24=49.2+24=73.2\ ft

6 0
2 years ago
Please help me with this
TEA [102]

Answer:

6y

Step-by-step explanation:

The two figure are squares with the same area

side = √area = √y^2 = y (with y>0 because a length can‘t be negative)

perimeter = side * 6 = y * 6 = 6y

5 0
2 years ago
solve the equation. Justify each step. 5x - 11 = 34 Plzzz help me this needs to be explained in essay form.
Helga [31]

Answer:

x = 9

Step-by-step explanation:

5x -11 (+11) = 34 (+11)

5x = 45

5x ÷ 5 = 45 ÷ 5

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4 0
3 years ago
What is the value of x in the equation 1/5 x - 2/3 y = 30 when y=15
zubka84 [21]
To determine the value of X in the given equation substitute the value of y into the equation and solve for x.

1/5x - 2/3y = 30
1/5x - 2/3(15) = 30
1/5x -10 = 30
1/5x - 10 + 10 = 30 + 10
1/5x = 40
1 = 5x • 40
1 = 200x
X = 1/200.
4 0
2 years ago
Hello please help me need aanswer​
Vika [28.1K]

\bold{\huge{\purple{\underline{ Answers :- }}}}

<h3><u>Answer </u><u>1</u><u> </u><u>:</u><u>-</u></h3>

If I were one of the students in Barangay then I shall prepare the design of kite by using the known properties of kites in mathematics.

For example, Symmetrical about its main diagonals, Adjacent side equals, Having two pairs of congruent triangle etc.

<h3><u>Answer </u><u>2</u><u> </u><u>:</u><u>-</u><u> </u></h3>

Design of kite assign to me

<u>Step </u><u>1</u><u> </u><u>:</u><u>-</u>

  • I shall take one paper and cut it like that the adjacent sides of paper are equal

<u>Reason </u><u>:</u><u>-</u>

  • <u>Adjacent </u><u>sides </u><u>of </u><u>kite </u><u>are </u><u>equal </u>

<u>Step </u><u>2</u><u> </u><u>:</u><u>-</u>

  • I shall take two thin sticks and paste it on the paper but sticks should intersect each other at 90°

<u>Reason</u><u> </u><u>:</u><u>-</u>

  • <u>Kite</u><u> </u><u>has </u><u>2</u><u> </u><u>diagonals </u><u>which </u><u>intersect </u><u>each </u><u>other </u><u>at </u><u>9</u><u>0</u><u>°</u><u> </u><u>.</u>

<u>Step </u><u>3</u><u> </u><u>:</u><u>-</u>

  • <u>Make </u><u>a </u><u>hole </u><u>in </u><u>the </u><u>one </u><u>of </u><u>the </u><u>end </u><u>point </u><u>of </u><u>a </u><u>longest </u><u>sides</u><u>. </u>

<u>Observation </u><u>:</u><u>-</u>

  • <u>The </u><u>kite </u><u>should </u><u>be </u><u>looked </u><u>like </u><u>that </u><u>it </u><u>having </u><u>two </u><u>pairs </u><u>of </u><u>congruent </u><u>triangle</u><u> </u><u>with </u><u>common </u><u>base. </u>

<h3><u>Answer </u><u>3</u><u> </u><u>:</u><u>-</u></h3>

  • The adjacent sides of the kites are equal that is 4cm and 6cm
  • The diagonals of the kite bisect each other at 90°
  • As kite is symmetrical from main diagonals , so it has two opposite and equal Angles that is 127°
  • The opposite angles at the end points of kite are congruent that is Angle D and Angle C
  • AC is the bisector of AB and AB is the bisector of AC .

[ Note :- Kindly refer the above attachment ]

<h3><u>Answer </u><u>4</u><u> </u><u>:</u><u>-</u></h3>

All mathematical concepts used in making kite are as follows :-

  • <u>Adjacent </u><u>sides </u><u>are </u><u>equal </u>
  • <u>Diagonal </u><u>intersect </u><u>each </u><u>other </u><u>at </u><u>9</u><u>0</u><u>°</u>
  • <u>Having </u><u>two </u><u>pairs </u><u>of </u><u>congruent </u><u>triangle </u><u>with </u><u>common </u><u>base </u>
  • <u>Symmetrical </u><u>about</u><u> </u><u>its </u><u>main </u><u>diagonal</u>
  • <u>Opposite </u><u>angles </u><u>at </u><u>the </u><u>end </u><u>points </u><u>are </u><u>equal</u>

3 0
2 years ago
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