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Alborosie
3 years ago
8

Solve the inequality -1/2x>2 and write the solution using:

Mathematics
2 answers:
irina1246 [14]3 years ago
6 0

Answer:

x > -4

Interval notation is (-4,∞)

Step-by-step explanation:

\frac{-1}{2} x>2

We need to get x alone

To get x alone , we need to remove -1/2 from left hand side

To remove denominator 2 we multiply both sides by 2

2*\frac{-1}{2} x>2*2

-1x> 4

To remove -1 , divide both side by -1

When we divide or multiply by negative then reverse the inequality symbol

x > -4

Interval notation is (-4,∞)


quester [9]3 years ago
3 0

<u>Answer:</u>

x

<u>Step-by-step explanation:</u>

We are given the following inequality and we are to solve it for x:

- \frac { 1 } { 2 } x > 2

To solve this, we will multiply the denominator -2 with the other side of the inequality to separate the variable x and make it the subject.

x>2(-2)

Also, since the negative sign is multiplied so the inequality sign will be reversed to '<'.

x


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Find the complex fourth roots of 81(cos(3pi/8) + i sin(3pi/8))
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By using <span>De Moivre's theorem:
</span>
If we have the complex number ⇒ z = a ( cos θ + i sin θ)
∴ \sqrt[n]{z} =  \sqrt[n]{a} \ (cos \  \frac{\theta + 360K}{n} + i \ sin \ \frac{\theta +360k}{n} )
k= 0, 1 , 2, ..... , (n-1)


For The given complex number <span>⇒ z = 81(cos(3π/8) + i sin(3π/8))
</span>

Part (A) <span>find the modulus for all of the fourth roots
</span>
<span>∴ The modulus of the given complex number = l z l = 81
</span>
∴ The modulus of the fourth root = \sqrt[4]{z} =  \sqrt[4]{81} = 3

Part (b) find the angle for each of the four roots

The angle of the given complex number = \frac{3 \pi}{8}
There is four roots and the angle between each root = \frac{2 \pi}{4} =  \frac{\pi}{2}
The angle of the first root = \frac{ \frac{3 \pi}{8} }{4} =  \frac{3 \pi}{32}
The angle of the second root = \frac{3\pi}{32} +  \frac{\pi}{2} =  \frac{19\pi}{32}
The angle of the third root = \frac{19\pi}{32} +  \frac{\pi}{2} =  \frac{35\pi}{32}
The angle of the  fourth root = \frac{35\pi}{32} +  \frac{\pi}{2} =  \frac{51\pi}{32}

Part (C): find all of the fourth roots of this

The first root = z_{1} = 3 ( cos \  \frac{3\pi}{32} + i \ sin \ \frac{3\pi}{32})
The second root = z_{2} = 3 ( cos \  \frac{19\pi}{32} + i \ sin \ \frac{19\pi}{32})

The third root = z_{3} = 3 ( cos \  \frac{35\pi}{32} + i \ sin \ \frac{35\pi}{32})
The fourth root = z_{4} = 3 ( cos \  \frac{51\pi}{32} + i \ sin \ \frac{51\pi}{32})
7 0
3 years ago
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