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Lady bird [3.3K]
3 years ago
5

John wants to simplify the expression (5+3) to the power of 2. As a first step, he writes 5 to the power of 2+3to the power of 2

. Will he get the correct value for the expression? If not, what should he do to simplify the expression
Mathematics
1 answer:
Anna35 [415]3 years ago
6 0
No, he needs to do 5(to the power of 2) plus 3(to the power of 2)
this should give him 25 plus 9 = 34
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Which expression represents the greatest common factor (GCF) of 70 and 112? A. 2 x 2 x 2 x 7 B. 2 x 2 x 2 x 5 C. 2 x 7 D. 2 x 2
Mekhanik [1.2K]

Answer:

\huge\boxed{C. \ \ GCF = 2 * 7}

Step-by-step explanation:

<u>Firstly, we'll do prime factorization of these numbers.</u>

70 = 2 × 5 × 7

112 = 2 × 2 × 2 × 2 × 7

<u>So, The Greatest Common Factor can be written as:</u>

GCF = 2 × 7    <u>[Since Only one 2 and one 7 is common]</u>

<u></u>

Hope this helped!

<h2>~AnonymousHelper1807</h2>
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3 years ago
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Nutka1998 [239]

Answer:

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2 years ago
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In the figure above, quadrilateral ABCD is a parallelogram. Let x represent the measure of angle GBF, y represent the measure of
ira [324]
Answers:
measure angle x = 40°
measure angle y = 35°
measure angle z = 55°

Explanation:
Part (a): getting angle x:
In triangle BED, we have:
measure angle BED = 90°
measure angle BDE = 50°
Therefore:
measure angle DBE = 180 - (90+50) = 40°
Now, we have angle DBE and angle GBF vertically opposite angles.
This means that they are both equal. Therefore angle GBF = 40°
Since angle GBF is x, therefore:
x = 40°

Part (b): getting angle y:
We know that the sum of measures of angles on a straight line is 180.
This means that:
angle GBF + angle GBC + angle CBE = 180
We have:
angle GBF = 40°
angle GBC = 105°
angle CBE = y
Therefore:
40 + 105 + y = 180
y = 35°

Part (c): getting angle z:
In triangle BCE, we have:
measure angle BCE = z
measure angle BEC = 90°
measure angle CBE = 35°
Therefore:
z + 90 + 35 = 180
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Hope this helps :)

8 0
3 years ago
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Answer:

<h2>\frac{1}{2}</h2>

Solution,

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Now,

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Answer:just drag across

Step-by-step explanation:

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