Answer:
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Step-by-step explanation:
A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).
<h3>Calculate the vertices of ΔA'B'C':</h3>
Given that,
ΔABC : A(-6,-7), B(-3,-10), C(-5,2)
(x,y)→(x,y-3)
The vertices are:
- A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
- B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
- C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)
Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).
Learn more about translation rule:
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Answer:
$351,000
Step-by-step explanation:
Your welcome
1800x6.5x30
To change it into slope intercept (y=mx+b) you just replace the inequality with an equality and isolate y
x<=2:
x=2=y-> y=2 or y=2+0x
2x-3y>=4:
2x-3y=4
2x-4=3y
(2/3)x-(4/3))=y
y=(2/3)x-(4/3)
x+y>0:
x+y=0
y=-x or y=-x+0
