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3 years ago

What is the sum? 2x over x^2 + x-4 over 9x

Mathematics

1 answer:

Allushta [10]3 years ago

4 0

Answer:

Step-by-step explanation:

2x/x^2 + x-4/9x = 2/x + (x-4)/9x {LCM = 9x}

= 2*9/x*9 + (x-4)/9x

= 18/9x + (x-4)/9x

= 18 + x -4 / 9x

= 14 + x /9x

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Americans eat an average of 100 acres of pizza per year. That is equivalent to 4,356,000 square feet of pizza per year. How is t

Maru [420]

Answer:

D. $4.356 * 10^6$ ft²

Step-by-step explanation:

Scientific notation of a number is expressed in the following form, $a * 10^b$

Where,

a = decimal number (1 ≤ |a| < 10)

b = the power of 10 whereby the scientific notation is equivalent to the original number.

To express 4,356,000 square feet in scientific notation, do the following:

1. Move the decimal point to the left up to the last non-zero digit = a = 4.356

2. Since we moved the decimal point by 6 decimal places, therefore, b = 6

3. Substitute the values of the variables into

Thus:

4,356,000 = 3. Substitute the values of the variables into

a * 10^b

Thus:

4,356,000 = 4.356 * 10^6

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2 years ago

Describe how to multiply a number by a power of 10

aev [14]

When multiplying a number by the power of 10, you are multiplying that number by itself 10 times. EX: 5^10 = 5 * 5 * 5 * 5 * 5 * 5 * 5 * 5 * 5 * 5

6 0

3 years ago

The sum of two numbers is 52. The greater number is 4 more than the smaller number. Which equation can be used to solve for the

Oliga [24]

Answer:

x+(x+4)=52

Step-by-step explanation:

let the small number be x

The greater number is 4 more than the small number=x+4

sum of numbers= x+ (x+4)

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3 years ago

The length of pregnancy isn’t always the same. In pigs, the length of pregnancies varies according to a normal distribution with

Nesterboy [21]

a. percent of pig pregnancies that are longer than 106 days

Since we have a normal distribution here and the average number of days is 106, we can say that 50% of the pig pregnancies are longer than 106 days.

b. percent of pig pregnancies that are shorter than 111 days

To get the percentage, we will have to convert x = 111 days into a z-score first. The formula is:

$z=\frac{x-\mu}{\sigma}$

where x = raw data, μ = population mean, and σ = population SD.

Since these 3 pieces of information are already given in the question, let's plug them into the equation above.

$z=\frac{111-106}{5}=\frac{5}{5}=1\sigma$

Therefore, 111 days is located 1 standard deviation to the right of the mean.

To find the percentage of pig pregnancies shorter than 111 days, we need to find the area covered to the left of 1 SD.

To find the area covered to the left of 1SD, we need to use the standard normal distribution table.

Based on the table, the area covered to the left of 1SD is 0.8413. Multiplying the area by 100, we get 84.13. Therefore, 84.13% of the pig pregnancies are shorter than 111 days.

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1 year ago

40% of the tickets sold at a school carnival were early-admission tickets. If the school sold 65 tickets in all, how many early-

kupik [55]

Answer:

Step-by-step explanation:

0.40 x 65 = 26

65 - 26 = 39

The school sold 39 early-admission tickets.

7 0

2 years ago

Read 2 more answers